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thanks bro!

Convert to an equation: 2/100 = x*4/10 ==> x = 1/20.

This translates to 5%.  Hope this helps!

Can you please elaborate and share how you got that solution?

The remainder is 4.

All of the tringle's angles sum up to 180 degrees. So we have to subtract the sum of 84 and 43 from 180 to get 53 degrees as our answer 

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That doesn't make sense! If the minute moves 30 degrees per 5 minute interval, then 30*10 = 300 degrees should be the degrees the minute hand travels until 10!

WXZ is a straight angle, which 180 degrees. Our equation is YXW + YXZ = 180 degrees. In other words; x + 28 + 3x + 2 = 180 degrees. So we simplidy and get 4x = 150. 150 / 4 is 37.5, so x = 37.5 

Oh no, sometimes things glitch. :((

Try reposting the question?

=^._.^=

YXW  +  YXZ     =  180

So

x + 28   +  3x  +  2  =   180

4x   +  30   =  180

4x =   150

x =   150 / 4    = 75 / 2     =    37.5°

We  have  a  10- 24 - 26  right  triangle

Area   =  10  *  24   /  2     =    120

Circumcenter is  at  the  midpoint of the hypotenuse  and  the  circumradius  =  26/ 2  =   13

So   area of  circumcircle  =    pi * 13^2   =   169  pi

a -  b    =

169 pi   - 120

I just got lucky  ......LOL!!!!!

Let  M  be  the  number of  minutes  after  10

The hour  hand  moves   (1/2)°  every minute

The  minute  hand  moves  6°  every  minute

Call   10 o'clock   =  0°

So....the  minute  hand is  at  60°   at 10

So.....we  just need to solve  this

6M  - (1/2)M  +  60 =   90

5.5M     =   30

M =  30  / 5.5  ≈  5.45  minutes  after  10   =  5  + .45 *60   ≈  5 min 27 sec  after 10

Totally wasn't thinking about using a graph for this...that makes so much more sense!

Thanks, Jugoslav.  I'm the "guest" who gave the first answer up there.  I knew Techno's answer was wrong, but I was reluctant to point that out.  For one reason, the inaccuracy is obvious.  But the main reason was that I, as having given the correct answer, didn't want to be the one to b**w the whistle.  I'm glad you came along to clear up the matter.  ~Ron  

_.

I believe the solutions to the given equations cannot both be integers if we assume m is an integer, so the problem is unsolvable as stated, and here is a proof; see if you agree with me.

I. For the quadratic equation \(a{x}^{2}+bx +c=0\), the sum of the roots is \(-\frac{b}{a}\), and the product of the roots is \(\frac{c}{a}\).

II. The given quadratic equation, therefore, has the following as the sum and the product of the roots:

                                                                              \(product=\frac{m-8}{m}=1-\frac{8}{m}\)

                                                                               \(sum =\frac{m-2}{m}=1-\frac{2}{m}\)

III. The sum and the product of two integers are always integers. So the expressions given above are both integers,

IV. What integer values for m result in an integer value for \(1-\frac{2}{m}\)? m, being an integer, must clearly be 1, -1, 2, or -2.

V. The following table tabulates the sum and the product for each of the four values for m. None of the four pair of values give integer values for the roots.

See  here   :  https://www.desmos.com/calculator/n4del4rlti

If  x   =  one number  and  y  the other......we  have  the  area of a quarter-circle  of  a  radius of   1  centered at  the origin  ....  area   =  pi/4

And  the  total possible  area  =  a  2 x 2   square =   area of  4

So.....the probabilty  is

pi  / 4                       pi

_____       =         ____

    4                         16

Applying Euclidean's algorithm, we get:

\(\gcd(3n+4, n) \\=\gcd(3n+4-3n, n)\\=\gcd(4, n)\)

The factors of 4 are 1, 2, and 4. Sum them up and you'll get the answer.

See here   :   https://www.desmos.com/calculator/tscjmguugt

Range    = (-inf ,  inf )

The  hour  hand   moves    (1/2)°  every  minute  =  30 degrees every hour

Taking   staight  up   12   as  0°

At   6  minuttes  afier   12   the  hour  hand  is at   6  (1/2) =   3°

At   2  minutes  after  5  the  hour   hand  is  at    5*30  +  2(1/2)   =  151° 

So....from   12:06 AM  to   5:02 AM  the  same  day  it  ,moves   151  -  3   =   148°

And it  will move    24 * 60  * (1/2)  =   720°   more   from  5:02  AM  one day to  5:02  the  next day

So

148   +  720   =  

868°

Just a bit of algebra will do it.

\(\alpha +2\beta =180\)                                                               (1)

\(\alpha +\beta +\delta +\gamma =180\)                                                  (2)

\(\beta +\delta -\gamma =49\)                                                            (3)

Subtract (2) from (1)  to get

\(\beta -\delta -\gamma =0\)                                                               (4)

Solvinf (4) for \(\beta -\gamma \) and substituting that in (3) results in

\(\delta +\delta = 2\delta =49\),

which gives you \(\delta =24.5\).

Note  that    a^10  * b^10   =  (ab)^10....so

(1 + x) ( 1 - x)  = (  1  - x^2)

So

( 1 + x)^10  *  ( 1 - x)^10    =

( 1 -  x^2) ^10

And  by  the Binomaial   Expansion .......   ( a + b)^n    will  have  n + 1  terms

So

n + 1 =   10   + 1   =   11  terms

2 /  ( 2 + 3 + 3)    *   180   =

2 /  8   *     180

(1/4)  *  180   =

45°

If you stack 3 pieces of bread would it be a stack of bread or a bread sandwhich?   

I think you could call it a jam sandwich ... because it's three slices of bread jammed together.  < rimshot >   

_.

This  simplifies  to     (x - 1)^2  /  ( x + 2)

We  wil have  a "hole"    at    x   = 1    ⇒   (1,0)

A vertical asymptote  at    x =  -2

And a "slant"  asymptote  found  as  follows

                x   - 4

x + 2  [    x^2    -  2x     +   1]

               x^2   +  2x

            ____________________

                           -4x   +    1

                           -4x   -    8

                         _____________

Slant  asymptote   y =   x   - 4

See the graph here  :   https://www.desmos.com/calculator/7hyqb8rhxb