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y + 3/5 = - x     in point -slope form

R = 3/4        W = 1/4

3/4(5/9) = 5/12    (Red beads)

1/2 - 5/12 = 1/12    (White beads)

Cookie =m
Cake= m+70 cents

4 cookies =4 m
2 cake = 2m+140 cents
Total= (6m + 140) cents

3 cake = 3m + 210
2 cookies = 2m
Total = 5m + 210
If m=80 cents, 
Therefore total = 5x80 +210 =610.
Alison have 610 - 25 = 585 cents.

Slope = ( -4-2)/(7- -1) = -6/8 = -3/4

Point slope form is then   (pick either point)

y-2 = -3/4(x +1)

cookie = m cents

cake = cookie + 70    =   m+70

a)

2 *cake + 4* cookie

= 2* (m+70)   + 4*m

= 6m+140

b)   m = 80     so  cookie = 80 cents     and cake = m+70 = 80 + 70 = 150 cents

    3 * cake   + 2*cookies

    3* 150     + 2 * 80 = 610 cents

       If Alison is 25 cents short   she has   610 - 25 =  585 cents

If the number of planets in our solar system were squaered, there would be this number of planets.   

A moving object had been newly discovered in the Solar System as early as 1909 but astronomers had not realized it was an orbiting body.  In 1930, the discovery was recognized as a planet and was named Pluto, at the suggestion of 11-year-old schoolgirl Venetia Burney. 

Pluto remained a planet until the International Astronomical Union decided it didn't conform to their definition of a planet and downgraded it to "dwarf planet" status.  Enough authorities have gone along with that decision to make it stick.  But the IAU is not the boss of me, and I still consider Pluto a planet.  So I say there are still 9 planets, and 9 squared is 81. 

But be aware that, if you submit 81 as your answer, your teacher will mark it incorrect.  For self-preservation, go with 64, as previously answered.  However, I'm obstinate and stand on principle, at least as long as it doesn't cost me too much. 

_.

19  17

18  18

17  19

are the only rolls out of    20^2    that produce  36    

              3/400

We need point P that is 1 /(1+2) = 1/3 of the way from P to Q

  for x    from 4 to 10        1/3 of the way would be   6

  for y    from  5 to 14        1/3 of the way would be  8                    (6,8)

(sqrta x +3)^2 = ax^2 + 15x + 9     expand the binomial on the L side

 ax^2 + 6 sqrt a + 9 = ax^2 + 15x + 9

so    6sqrt a = 15

          sqrt a = 2.5

          a = 6.25

Hello Guest!

\(f(x) =|\ \sqrt{25-(x-4)^2}\ |\)         domain is [-1, 9]

\(g(x) =|\sqrt{25-(x-4)^2}\ |^2\)           domain is [-1, 9]

  !

https://web2.0calc.com/questions/geometry-help-asap-pls_1#r2

https://web2.0calc.com/questions/hello-any-help-is-greatly-appreciated#r6

17х-28=9х+44

17x-9x=44+28

8x=72

x=9

If you don't count Pluto ( or the three other dwarf planets)  as a planet (many do not)     8 * 8 = 64 planets 

This from WolframAlpha ....I do not know how to derive it ( except for the decimal approximatio listed):

It will be whatever is in the units place....         5432      r=  2                 46789      r = 9

Number is   xy

(10x + y) * 5   = (10y+x) 6

50x+5y = 60y+ 6x

44x = 55y   

x = 55/44 y

x = 5/4 y            

x/y = 5/4               x = 5   y = 4               5+4 = 9

B=2pi(R+T/2)(A/360)      Divide both sides by 2 pi

B/2pi =  (R+T/2)(A/360)     Now mutiply both sides by   360/A

360AB/2pi = R+ T/2            Now subtract R from both sides

360AB/ 2pi    - R    =   T/2      now multiply both sides by 2    <=======I'll let you finish !

 he can have   O  - letter-  O

                        O               E

                        E               E

                        E               O

3/4 chance it contains an odd single digit

CLOSE HW...but not quite

   - b/2a = -45/-30 = 1.5  seconds     the TIME the ball is at a maximum

         you must sub t = 1.5 into the equation to get the maximum HEIGHT ....

97 * 86

y=49 in that case but try reading that again and really think about I t

They both have 15x on the left side

If you TAKE the second left side of the first left side you will get rid of the x'es

The whole aim is to get rid of one of the letters.   Sometimes you add and sometimes you minus.

15x-2y=16

15x-7y=51

15x-15x   -2y- -7y = 16-51

       0       -2y + 7y = -35

                     5y     =  -35

                      y      =   7

now substitute to get x

What is the greatest integer solution to pi*x - 17 < 20^2?

Hello Guest!

\( \pi x - 17 < 20^2\\ x<\dfrac{400+17}{\pi}\\2164.507<\dfrac{400+17}{\pi}\ \color{red}not\ correct\)        Thanks alan!

The greatest integer solution to pi*x - 17 < 20^2 is 2164.\( \color{red}not\ correct\)

\( \pi x - 17 < 20^2\\ x<\dfrac{400+17}{\pi}\\132.73<\dfrac{400+17}{\pi}\ \)

The greatest integer solution to pi*x - 17 < 20^2 is 132.

  !

Since the leading coefficient is negative, the quadratic opens downward.

The maximum height of the ball is the vertex of the parabola. Formula for the vertex is -b/2a with quadratic equation ax^2+bx+c

So the answer is -45/-30=1.5 feet.

Hope that helps