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The ratio is 9/16

3^(2n) + 4  

You have the first three    then comes    sqrt 250     sqrt 1250  sqrt 6250       sqrt 31250    <===== simplify as needed

The result of adding the functions will result in the same degree as g(x )     degree 4

none

Uhhh.... there is no diagram ! 

....make sure you use cos 135   if using cos law for this problem !

64   I think

(3 + 4 sin 45)^2   +  (4 cos 45)^2   = d^2     d= 6.478 miles   (6.48 miles   rounded)

Not really a rectangle....but here is a picture ...you can count them:

The 8 corner ones

wrong

By the cosine law, Jane will be 5.8 units from her starting point.

Wrong

1. How many ways can you choose 3 points - how many ways can you choose 3 points that form a line?

2. If you connect two right isosceles triangle with a hypotenuse of 1 by the hypotenuse, you get a sqaure. Find the area of the square/2.

:))

=^._.^=

s + 2(sin45º * s) = 1

s = 0.414213562       or  √2 - 1

Multiply the numerator and denominator by   sqrt(2)  -  sqrt(5)   to rationalize

At what point does the graph of 3x+4y=15 intersect the graph of x^2+y^2=25?

Hello Guest!

\( \frac{15-3x}{4}=\sqrt{25-x^2}\\ 225-90x+9x^2=16\cdot 25-16x^2\\ 25x^2-90x-175=0\\x^2-\frac{18}{5}x-7=0\\ x= \frac{9}{5}\pm \sqrt{\frac{81}{25}+7}\\ x=\frac{9}{5}\pm \frac{16}{5}\)

\(x\in \{-\frac{7}{5},5\}\)

\(y\in \{\ \frac{24}{5},\ 0\}\)

  !

1st red   2nd red

1 st red   2nd other

1 other    2nd red   are the possibles

6/11 * 6/11     +   6/11 * 5/11   +   5/11 * 6/11   =   ( 36 + 30 + 30)/121    = 96 / 121       ( not positive)

XZ = 4√8 

r = orange number

g = 2r + 8                         summed, these = 59

r      +   2r+8       = 59

 r = 17       then g = 2r+8 = 42

In ABC, we have AB=16, BC=14, and Angle A=60. Find the sum of all possible values of AC.

Let the line segment CD be perpendicular to AB.

AD = x

x√3 = sqrt[14² - (16 - x)²]

x = 3,     x = 5

AC = 3/cos(60º) = 6

AC = 5/cos(60º) = 10

The sum of all possible values of AC = 16

...did you multiply by the 'pi' before you just  took and ran with the numerical answer?