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end in

04, 08, 12, ..... 96

96/4 = 24

Both of those absolute values will be great or equal to zero.

The only time the denominator will be zero is when both absolute expresssions are = 0

so   

\(x^2+3x-4 =0\qquad and \qquad   x^2+9x-10 = 0\\ (x+4)(x-1)=0 \qquad and \qquad   (x+10)(x-1) = 0\\ so \qquad x=1 \)

the only real value of x are not in the domain of  f(x) is 1

Here is the graph:

Have you even attempted to work out what the dimensions of all the different bits are?

Have you done anything at all towards answering this?

\(7\sqrt[3]{x}=x+8\\ 343x=x^3+3*x^2*8+3*x^1*64+8^3\\ 343x=x^3+24x^2+192x+512\\ 0=x^3+24x^2-151x+512\\\)

1) I answered something similar today, have you bothered to look?

2) If you present your question properly more people are likely to respond.

3)  What have you tried for yourself?

we know the point of intersection is (-4, -7), so k has to be 0 since the y intercept of the equation y = kx - 7 is (0, -7), it follows that the line is horizontal therefore it has a slope of 0. 

wrong

There are 24 four-digit palindromes that are multiples of 4.

The inverse of h(x) is sqrt(2x - 3)/2.

g(f(-3)) = -9.

Let f(x) = 3x - 8 and g(f(x)) = 2x^5 - 5x - 3. Find g(-5).

f(x)=-5

3x-8=-5

3x=3

x=1

g(-5)=g(f(1)) = (2*1^5)-(5*1) -3 = 2-5-3 = -6

The multiplicative identity is the number 1 because if you multiply any number by 1, you will get, as a result, the number that you started with. (You will have an answer that is identical to the number that you started with.)

A multiplicative inverse is the number that, when multiplied to the original number, will have a result of 1.

Thus, the multiplicative inverse of 2 is 1/2; the multiplicative inverse of 3 is 1/3;

the multiplicative inverse of 23 is 1/23; the multiplicative inverse of 3/4 is 4/3;

the multiplicative inverse of -1/3 is -3; etc.

The number zero has no multiplicative inverse; for all other numbers, the multiplicative inverse of x is 1/x.

Hahaha... this is a girl's question. That's why I didn't understand the question. 

my sisters and I all have 2 more sisters than brothers, which means I am a girl.

So that means there are 3 more girls in the family than boys.

there might be  5 girls and 2 boys   

there might be  6 girls and 3 boys  etc

each boy will have  4 more sisters and brothers.

As examples:

if there were  5 girls and 2 boys   Then each boy would have 1 brother and 5 sisters

there might be  6 girls and 3 boys     Then each boy would have 2 brothers and 6 sisters

Something's not right here.

If I have 2 brothers, I must have 4 sisters. In this case, each of my sisters has 3 sisters and 3 brothers!?

But, if I have ONLY 4 sisters and no brothers, then each of my sisters has 3 sisters and 1 brother (2 more sisters than brothers).

What about the oldest brother?

\(y=log_{\frac{1}{3}}(\frac{\sqrt{27}}{3})\\~\\ y=log_{\frac{1}{3}}(\frac{\sqrt{3^3}}{3})\\~\\ y=log_{\frac{1}{3}}(\frac{3^{3/2}}{3^1})\\~\\ y=log_{\frac{1}{3}}(3^{1/2})\\~\\ y=log_{\frac{1}{3}}((\frac{1}{3})^{-1/2})\\~\\ y=\frac{-1}{2}log_{\frac{1}{3}}(\frac{1}{3})\\~\\ y=\frac{-1}{2}*1\\~\\ y=\frac{-1}{2}\\~\\\)

LaTex:

y=log_{\frac{1}{3}}(\frac{\sqrt{27}}{3})\\~\\
y=log_{\frac{1}{3}}(\frac{\sqrt{3^3}}{3})\\~\\
y=log_{\frac{1}{3}}(\frac{3^{3/2}}{3^1})\\~\\
y=log_{\frac{1}{3}}(3^{1/2})\\~\\
y=log_{\frac{1}{3}}(\frac{1}{3}^{-1/2})\\~\\
y=\frac{-1}{2}log_{\frac{1}{3}}(\frac{1}{3})\\~\\
y=\frac{-1}{2}*1\\~\\
y=\frac{-1}{2}\\~\\

ok thanks, I will look at it properly later on    

M --> Mario's

L--> Luigi's

According to question:

\( {M \over 4} = {9 \over 4}\)

4M = 9L ---- eq¹(1)

Again \( {M - 84 \over L } = {1 \over 2}\)
           2M - 168 = L ---- equation (2)

     Putting the value of in equation (1)

           4M = 9(2M - 168)

           4M = 18M - 1512

           14M = 1512

              M = \({1512\over14 } = 108\)
              M = 108

         the ratio have at first money is $108

You use the AM-GM inequality which says (a_1+a_2+a_3+...+a_n)/n >= nrt(a_1*a_2*...*a_n). Here's the art of problem solving article https://artofproblemsolving.com/wiki/index.php/Arithmetic_Mean-Geometric_Mean_Inequality

Two liters of a 30% acid solution are mixed with three liters of a $80\%$ acid solution. What percent of the mixture is acid?

Hello Guest!

\(0.3\cdot 2l+0.8\cdot 3l=x\cdot 5l\\ 5\cdot x=3 \)

\(x=\dfrac{3}{5}=0.6\)

60% of the mixture is acid.

  !

It was answered  in https://web2.0calc.com/questions/ratio_42

 How much money did Mario have at first?

Hello Guest!

\(m:l=9:4\\ l=\dfrac{4m}{9}\\ (m-\$84):l=1:2\\ l=2m-\$168\)

\(\dfrac{4m}{9}=2m-\$168\\ 4m=18m-\$1512\\ 14m=\$1512\)

\(m=\$108\)

\(Mario\ initially\ had\ \ \color{blue}$ 108.\)

  !

The difference between beef pies and chicken

pies = 70

Total pies sold in a day = 450 +121 =571

The difference in beef pies and chicken at the

end = -450 +121+70

    = -259

Ratio

Beef pies : Chicken Pies

5:12 = 5x/12x

12x -5x =259

7x =259

x=259/7

x=37

So,

total pies baked ,T(x)= 12x + 5x + Total pies sold in a day

                            T(x) = 17x + 571

                            T(37) = 17(37) + 571

Total pies Baked =1200   Answer

Okay, first we need to look at the question. If William NOW has 24 comic books, including the recently bought books and the previosly sold books. Our equation could look like this:

24 = (C / 2)+ 10

With the variable C being the amount of comic books William had before. We can solve this by subtracting 10 from 24 (24 - 10), to get 14 and multiply that by 2 to get 28 comic books. So, in summary, William would had have 28 comic books to begin with.