Answer:
\([200, 350)\)
Explanation:
Let \(x\) be the number of dollars in the pile of money. Since she puts \($50\) in her left pocket, gives away \(\frac{2}{3}\), of the rest of the pile, and then puts the rest in her right pocket, Jeri has \(50+\frac{1}{3}(x-50)\) dollars.
We also know that she would have more money than if instead she gave away \($200\) and kept the rest. With this information, we can write an inequality.
\(50+\frac{1}{3}(x-50)>x-200\) .
Multiplying each side by \(3\), gives us
\(150+(x-50)>3x-600\).
When we group like terms we get
\(x+100>3x-600\).
Then, we subtract \(100\) from both sides, giving us
\(x>3x-700\).
Subtracting \(3x\) from each side gives us
\(-2x>-700\).
When we multiply each side by \(-1\), this also reverses the inequality so, we have
\(2x<700\).
Dividing each side by \(2\), gives us
\(x<350\).
Since we know \(x\ge200\) but \(x<350\), we can write the interval \([200, 350)\).
\(\)
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