Slope is defined as rise/run if run = 0 (as a vertical line) then the slope is UNDEFINED .(zero in the denominator)
Look up information regarding the binomial theorem for further information.
\(\binom{6}{4}(2x)^4 (2)^2 = \boxed{960x^4}\)
The coefficient is 960.
V = a³
V = 5³ cm
V = 5 cm * 5 cm * 5 cm
V = 125 cm³
The coefficient of x^4 is 960x^4.
C. Negative
5 cm * 5 cm * 5 cm = 125 cm3
Note the vertex at 3, 8
vertex form y = a(x-3)^2 + 8 sub in a point to solve for 'a' I'll use 5,4
4 = a ( 5-3)^2 + 8
a = -1
y = -(x-3)^2 + 8 expand to y = -x^2 + 6x -1 <======== take it from here !
\(30 \times 1.4 = \color{brown}\boxed{42}\)
\(30\) is the original price, and \(1.4\) is the markup.
210?
Add (1) + (2) (both equations) together and you get 2x + 2y + 2z = 42 (3). Multiply the equation (3) by 5 and you get 10x + 10y + 10z = 42 * 5 = ............... (diy).
There are many, many of them such as:
33 = 3 * 11 34 = 2 * 17 35 = 5 * 7 85 = 5 * 17 86 = 2 * 43 87 = 3 * 29 93 = 3 * 31 94 = 2 * 47 95 = 5 *19
Wellllll..... round it to two decimal places.....you SHOULD know how to do THAT!!!
By complementary counting, there are 792 - 142 = 650 ways.
Wait... Never mind, my hint is wrong, sorry.
Hint: The consecutive series of positive integers should be numbers that have divisors, e.g. 9 and 10 are consecutive, where 9 = 3 * 3 and 10 = 2 * 5.
There are infinite solutions for x and y, when \(x \in \mathbb{P}\) and \(y = 1\), or \(x = 1\) and \(y \in \mathbb{P}\) .
Simply plug in the expression into the function.
a. f(1) = 3(1) - 2 = 1
b. f(t) = 3t - 2
c. f(x^2) = 3x^2 - 2
d. f(f(x)) = f(3x - 2) = 3(3x - 2) - 2 = 9x - 8
Let x be the number of apples Nicole has and y be the number of apples that Hannah has.
x/y = 1/3
(x + 4)/(y + 3) = 1/2
Rewrite the first equation to get y = 3x, then substitute into the second equation.
(x + 4)/(3x + 3) = 1/2
2(x + 4) = 3x + 3
2x + 8 = 3x + 3
5 = x
Nicole had 5 apples in the beginning, so Hannah had 15 apples in the beginning. In the end, Hannah had 15 + 3 = 18 apples.
1584 = 2^4 * 3^2 * 11
To be a perfect cube, a number's prime factors' exponents must all be multiples of 3. So, the smallest value of x is:
\(\frac{2^6 \cdot 3^3 \cdot 11^3}{2^4 \cdot 3^2 \cdot 11} = \boxed{1452}\)
In other terms, x = 1452 = 2^2 * 3 * 11^2. The product xy must be a multiple of 1584, so,
xy = 2^2 * 3 * 11^2 * y = 2^4 * 3^2 * 11 * n
y must have 2^2 * 3 as a factor, so the smallest value of y is 12.
Use the following algebraic identity:
(x + y + z)^2 = x^2 + y^2 + z^2 + 2(xy + xz + yz) = 9 + 2(18) = 45
i need the answer in two decimal places
\(\frac{1}{x} + \frac{1}{y} = \frac{1}{17}\)
\(\frac{x + y}{xy} = \frac{1}{17}\)
\(17(x + y) = xy\)
\(0 = xy - 17x - 17y\)
\(289 = (x - 17)(y - 17)\)
The possible values of x are 18, 34, and 306.
Thanx for finding my mistake !
Yah.....I manged to mix weekly and MONTHLY payments ....here is my corrected:
Present value of ordinary annuity
PV = C * ( 1-(1+i)-n ) /i i = .0279 / 52 n = 8 yr * 52 wks = 416 PV = 28250 find 'C'
C = payments = $ 75.787
Total payments = 416 * 75.787 = $ 31527.43 interest = 31527.4 - 28250 = $ 3277.43