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thanks!

The one that is not choosy is going to be a Setter.  That way there are 5 setters  and 5 spikers 

Take a setter, makes no difference which one.  She can be matched with any of 5 spikers

Take another setter.  She can be matched with any of the remaining 4 spikers.

etc

So the answer will be   5! = 120 ways

Don't know...I never use it

I prefer  WolframAlpha here   :  https://www.wolframalpha.com/input?i=sin+x+%3D+1%2F2

If you have a system of equations, type them in separated by commas

"If A-B-C "    doesn't have any meaning......did you omit part of this  ???

Call the center  ( x, y)

We have these 3 equations

(x - 6)^2  + ( y + 6)^2 = r^2       (1)

(x - 3)^2  +  ( y + 7)^2 =  r^2     (2)

(x - 3)^2 +  (y - 3)^2 =  r^2        (3)

Subtract the third equation from  the  second and  we  have

(y + 7)^2  - (y - 3)^2   =  0        simplify

y^2 + 14y + 49  - y^2 + 6y - 9  =  0

20y + 40  =  0

20y  = - 40

y = -40 / 20 =  - 2

Replace this value for y in the  first  two equations and  simplify

( x-6)^2  + ( -2 + 6)^2  = r^2      ⇒ x^2 - 12x + 36  + 16  = r^2     ⇒  x^2 -12x + 52  = r^2    ( 4)

(x - 3)^2  + (-2 + 7)^2 = r^2      ⇒  x^2 - 6x +  9   + 25  = r^2       ⇒  x^2  - 6x + 34  = r^2     (5)

Subtract (5) from (4)

-6x + 18  = 0

-6x  = -18

x = -18 / -6  =  3

The center is (3, -2)  and  to find the radius  we can  use (1)

(3-6)^2  + (-2 + 6)^2  = r^2

9  +  16  = r^2

25 = r^2       take the positive sqrt

5 = r

Here's a graph : https://www.desmos.com/calculator/hwro781e8y

Hey there, Guest!

So 12 dozen is equal to $18.

So 4 dozen is equal to \(\frac{1}{3}*18\) which is equal to $6.

Hope this helped! :)

( ﾟдﾟ)つ Bye

Radius: \(15.2 \div 2 = \color{brown}\boxed{7.6}\)

Area: \(7.6^2\times 3.14 = \color{brown}\boxed{181.3664}\)

Circumference: \(15.2 \times 3.14 = \color{brown}\boxed{41.728}\)

I will take a shot at 1. 

Subsitute 1 as n. 

This gives: \(5^2-1 \times a_2 = -1^1\)

Solving for the unknown, we find \(a_2 = 26\)

Subsituting 2 for n, we get: \(26^2-5a_3=-1^2\)

Solving for the unknown again, we find \(\color{brown}\boxed{a_3=135}\)

Thanks for the help! 

Thank you for the explanation!

1)   7125   -  2200   =   4925 kg of non-plastics

Pct  of non-plastics =   4925  /  7125    ≈    69%

2)    To  see  this   let's  double the amt she bought and the amount the  cat ate

So  she buys 100 kg  and the  cat eats 22 kg

So    100 - 22  = 78 kg are left

So      78 /  100  =   78%  left

3)   5 games  of the total number   (T) =  12.5%  =  .125

So  

5 / T  =   .125     multiply   both sides by  T

5 =  .125 T       divide both sides by  .125

5 / .125 =  T  =    40 games total

He must  have won   40 T - 5 he missed  =  35

There are 350 numbers in your list and ALL of them are prime numbers. There are NO COMPOSITE numbers!!

Since the right triangle is isosceles.....we need to first find the  equal legs of the right triangle

So we have...[by the Pythagorean Theorem ] 

L^2  + L^2  =  50

2L^2    =50

L^2   = 50  / 2

L^2  = 25        take the positive root

L =  5 cm =   the equal legs

The surface area  of  one of the right triangles = (1/2) ( product of the legs)   = (1/2)(5 * 5)  = 25/2  = 12.5 cm^2

But we have two of these  (at the bottom and top)  so the total surface area of top/bottom= 2*12.5 = 25cm^2

The area of  the sides  =  perimeter of the right triangle * height of prism

So   we  have  5 + 5 + sqrt 50  = 10 + sqrt 50  =  perimeter

So  area of sides =   [ 10 + sqrt 50 ] * 8  =  80 + 8 sqrt 50  ≈  136.57  cm^2

So  the total  surface area  =   [ 25  + 136.57 ] cm^2   =  161.57 cm^2   

2.      Note that we can express this in  a slightly different manner   :

We  can write

      6                                    6                                6                                        6                                                        

_____________   +    _____________   +     ______________   +  ... +  ____________

[2 (1) + 1]^2 - 1           [ 2(2) + 1]^2 -1              [ 2(3) + 1]^2 - 1                [2(n) + 1]^2 -1

Note  that

       6                           6                                  6                      3          [     1           1          ]

__________  =     ______________   =    __________  =   ____  *       ___  -   ____

(2n +1)^2 - 1         4n^2 + 4n + 1 - 1           4 (n^2 + n)            2          [     n         n + 1     ]

So  we  can write

(3/2)   [    1/ 1 -  1/ [ 1 + 1)   +    1/ 2  -  1 / (2 + 1)   +  1/3  -  1 ( 3 + 1) +  1/4 - 1/(4 + 1) +...+  1/n - 1/n+1)  ] =

(3/2)  [   1  - 1/2  + 1/2   - 1/3  + 1/3  - 1/4  + 1/4 - 1/5 + ..... + 1/n  - 1/(n+1)  ]   =  

(3/2)   [  1    -    1 / ( n + 1)  ]  

As  n approaches some  "large"  number,   1/ ( n + 1)     approaches  0

So.....the sum  is

(3/2)  [  1  +  0 ] =

(3/2) [ 1 ]  =

3/2

Try proofreading your question.   

Your wasting your own and everybody elses time.

I think that we need more info

Area of a square =  side^2

225 ft^2    = side^2                take the positive square root of both sides

sqrt ( 225 ft^2)  =  sqrt  (side^2)

15  ft =  side

And the perimeter of a square  =  4*side  = 4*15  =   60  ft needed

Follow Geno's advice --

You can check them at this site:

                https://en.wikipedia.org/wiki/List_of_prime_numbers

You can check them at this site:

                https://en.wikipedia.org/wiki/List_of_prime_numbers