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(x - x³ - x) · (x - 3x² + 4) =  (-x³) · (x - 3x² + 4) =  (-x³)·(x) + (-x³)(-3x²) + (-x³)(4)

                                                                         =  -x⁴ + 3x⁵ - 4x³

a)  11 x 0   +   12 x 1   +   31 x 2   +   26 x 3   =   ...

b)  11 x 0   +   12 x 1   +   31 x 2 / 2   +   26 x 3 / 2   =   ...

It's a rectangular prism.

LSA:  6 x 4   +   8 x 4   +   6 x 4   +   8 x 4  =   ...

TSA:  LSA   +    8 x 6   +   8 x 6  =   ...  

16 trays with 24 eggs in each tray

                   total 16 * 24 eggs.

he fell and broke 1/3 of eggs.

                               broken eggs = 1/3 * 16 * 24

                                  good eggs = 2/3 * 16 * 24

    he sold 5/8 of good eggs.

                             sold = 5/8 * 2/3 * 16 * 24

                             remaining = 3/8 * 2/3 * 16 * 24

    he put remaining equally in 12 basket

             in one basket he put

                  = 1/12 * 3/8 * 2/3 * 16² * 24²

                  = 2 * 2 * 2

                  = 8 eggs in one basket

No picture.

Since we are to end with a fraction (or percentage), we may start with as many ounces as we wish.

Let's assume that there are 100 ounces in the punch bowl. Since one-half of it is fruit juice and 

one-half of it is Sprite:

Sprite = 50 ounces.     Fruit juice = 50 ounces.

One-fourth is poured out; this means that 25 ounces have been poured out; one-half of that is

Sprite and one-half is fruit juice. So, both Sprite and fruit juices lose 12.5 ounces.

Sprite = 37.5 ounces.     Fruit juice = 37.5 ounces.

Now, 25 ounces of Sprite are added.

Sprite = 62.5 ounces.     Fruit juice = 37.5 ounces.     Total  = 100 ounces.

What fraction is Sprite?  62.5 ounces / 100 ounces  =  62.5%  or  5/8^ths.

Let x be the total cookies at first.

3/4x + 24 - 36 - 30 = 0

3/4x = 42

     x = 56

Alex had 56 cookies in the jar at first

Similar question here: https://web2.0calc.com/questions/help-for-school-hw

Geno, your answer would be great if it was 199! but it isn't.  All the even numbers are missing.

odd multiples of 3,    6n-3  from n=1 to   n=round down[(199+3)/6] = 33          33 of them

odd multiples of 9      9,27,.....189                 9*1 to 9*21                                  11  of them

odd multiples of 27     27  ,...  179                 27*1 to 27*7                                        4 of them

odd multiples of 81     81  that is the only one                                                          1 of them

33+11+4+1 = 49

So guest and I agree.  But i used Genos method  :)

According to WolframAlpha website calculator:

3x^5 - x^4 - 4x^3

g(x) = -.03x^2+x+6=0

0= -.03x^2+x+6

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\\ x = {-1 \pm \sqrt{1^2-4*-0.03*6} \over 2*-0.03}\\ x = {-1 \pm \sqrt{1+0.72} \over -0.06}\\ \)

you can simplify it,

I have a different answer:

199 / 3  =  66.3333... which to me indicates that there are 66 numbers

between 1 and 99 that each has a factor of 3     --->     66

199 / 9  =  22.1111... which to me indicaets that there are 22 numbers

between 1 and 99 that each has a second factor of 3     --->     22

199 / 27  =  7.370... which to me indicates that there are 7 numbers

between 1 and 99 that each has a third factor of 3     --->     7

199 / 81  =  2.456... which to me indicates that there are 2 numbers

between 1 and 99 that each has a fourth factor of 3     --->     2

Therefore, i arrive at 66 + 22 + 7 + 2  =  97 factors of 3.

10 choices for first position

     9 choices for second position

          8 choices for third

              7 for 4th

                  and 6 choices left for the final position

10 * 9 * 8 * 7 * 6 = 30240 ways   

See https://web2.0calc.com/questions/help-asap-also-provide-how-u-got-ur-answer#r1

Why are you asking this here? Just PM him.

Add the two equations together.....this will eliminate 'y' and allow you to solve for 'x'

   use this value of 'x' in one of the equations to solve for 'y'

ty S2

B. Run

S ==0.1502570505 

T==1.051799728

S / T ==0.1502570505 / 1.051799728 == 1/7

199!! [double factorial] == 3^49 × 5^25 × 7^16 × 11^10 × 13^9 × 17^6 × 19^5 × 23^4 × 29^3 × 31^3 × 37^3 × 41^2 × 43^2 × 47^2 × 53^2 × 59^2 × 61^2 × 67 × 71 × 73 × 79 × 83 × 89 × 97 × 101 × 103 × 107 × 109 × 113 × 127 × 131 × 137 × 139 × 149 × 151 × 157 × 163 × 167 × 173 × 179 × 181 × 191 × 193 × 197 × 199.

As you can see, the largest n==49

This question was answered just a few days ago.

Thanks so much!

Thanks!