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In  5sin²x -3cosx = 4      either change the sin into cos or the cos into sin.

If you use the Pythagorean identity    sin²x  +  cos²x  = 1,

    you can get   sin²x  =  1  -  cos²x 

Substituting that into the original equation:

      5sin²x -3cosx = 4    --->   5( 1 - cos²x ) - 3 cos x  =  4

      Multiply out              --->   5 - 5 cos²x  - 3 cos x  =  4

      Write as a quadratic  --->  -5 cos²x  -  3 cos x  +  1  =  0

       Simplify                  --->    5 cos²x  +  3 cos x  -  1  =  0

Use the quadratic formula to get values for cos x; then use invcos x to get solutions.

If by   -2.3567 x 10^-35 / 6.022 x 10^ 23    you mean    ( -2.3567 x 10^-35 ) / ( 6.022 x 10^ 23 ),

this part of the problem becomes ( -2.3567 ) / (  10^35 x 6.022 x 10^ 23 ),

which becomes  ( -2.3567 ) / (  6.022 x 10^ 57 ),

which is so small that it does not affect  6.022 X 10^23,     (if that is what you meant to type)

so that is the answer.

=0.11111111111111111111111111111111111111111111111111111111111111111...

∞ x 1 / ∞  

is an "indeterminate"; that is, it can have different answers depending upon the problem that created the situation.

If may end up being ∞ , but it can also end as any real number. 

WHAT U SAID DIDNT MAKE ANY FRECKIN SENSE!!!!!!!

10+9=19 duhh

The greatest that you can decrease most items is 100%.

If you decrease an item by 100%, it then disappears.

However, if you can have a negative answer, then do this:

    Find 145% of 84     --     which is 1.45 x 84  or 121.80

    Subtract this amount from the original amount:    84  -  121.80   =  -37.8

Note: to find 145% of 84:

  to change 145 into a decimal, divide by 100, which moves the decimal point two places to the left

  interpret the word "of" as times

So, 145% of 84    becomes    1.45 x 84 

Yes. Depends on the expression you are using. 

No.

$$9+10=19$$

$$2*2=4$$

First, find the cost for each textbook by dividing the total cost by the number of textbooks:

    $124.00 ÷ 8  =  $ 15.50

Second, find the difference between what you sold it for and what you paid for it:

    $17.00  -  $15.50  =  profit made on each book.

The formula for compound interest is:  A  =  P( 1 + r/n ) ^ ( n · t )

where    A  =  final amount        P  =  amount invested       r  =  interest rate (as a decimal)

             n  =  number of times compounded per year         t  =  number of years

For this problem:    P  =  4500        r  =  .015       n  =  1 (since annually)       t  =  3

    A  =  4500( 1 + .015 / 1 ) ^ ( 1 · 3 )

    A  =  4500( 1 + .015 ) ^ 3

Place this into your calculator to find the final answer. 

I think that you typed something incorrectly because you have two equal signs in this equation. 

Was the original equation:  3/10x + 3/5 = 1 ?

If so, I would do it this way:

I would get rid of the denominators by multiplying both sides of the equation by 10.

10( 3/10x + 3/5 )  =  10(1)                       Multiply both sides by 10.

10( 3/10 ) + 10( 3/5 )  =  10                     Use the distributive property.

3 x + 6  =  10                                           Simplify.

3x  + 6 - 6  =  10 - 6                                 To get rid of the term '+ 6' subtract 6 from both sides.

3x  =  4                                                    Simplify.

3x / 3  =  4 / 3                                          To get rid of the 3 times x, divide both sides by 3.

x  =  4/3                                                   Simplify.

Since the cos(x) can never be greater than one, the left side of the equation can never be greater than 22.

Therefore, you have not created an equation.

$$-{\mathtt{61}} = {\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}\left({\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right){\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{b}} \Rightarrow {\mathtt{b}} = {\mathtt{2}}$$

$${\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{207}} = {\mathtt{210}}$$

$${\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{27}} = {\mathtt{30}}$$

210>30 thus yeah, it is.

May i ask how old u are? :)

it equals to 21 ;D

$${\mathtt{2.309\: \!82}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{5}}}$$

I got it. and I don't know why we need math lol it sucks.

$${\mathtt{13}} = {\frac{{\mathtt{1}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{7}}$$

$${\mathtt{13}}{\mathtt{\,-\,}}{\mathtt{7}} = {\frac{{\mathtt{1}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{x}}$$

$${\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{5}} = {\mathtt{x}}$$

$${\mathtt{x}} = {\mathtt{30}}$$

$${\mathtt{13}} = {\frac{{\mathtt{1}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{7}} \Rightarrow {\mathtt{x}} = {\mathtt{30}}$$

the factor you obsereve or measure during an experiment.

unidefined 

use the calculator $${\mathtt{m***n}} = \underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{m***n}}}$$

123/1000 123over 1000

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