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The sum of the interior angles of any triangle measure 180°

So..if all 3 angles are the same, each must measure 60°  .....!!!

You can change the problem like this:

10-[2+5/6]

now, subtract 2 from 10.

$${\mathtt{10}}{\mathtt{\,-\,}}{\mathtt{2}} = {\mathtt{8}}$$

Now, change 8 into 7 6/6

$$8\Rightarrow7\;\;\;6/6$$

Now, subtract 5/6 from 7 6/6.

$$7\;\;\;6/6-5/6=7\;\;\;1/6$$

Now, Change 7 1/6 into a fraction.

$$7\;\;\;1/6\Rightarrow\boxed{7\dfrac{1}{6}}$$

So, $$7\dfrac{1}{6}$$ is the final answer.

Yep.....it factors to 31 x 3.....remember a kind of neat trick....if the sum of the digits of a number is divisible by 3, then that number is also divisible by 3.  So,  93 = 9+3  = 12....and 12 is divisble by 3.... so 93 is, as well!!!

We can also find this by using the difference quotient and the binomial theorem......suppose we want to find the derivative of xⁿ   ...... so we have.....

lim          [ (x + Δx)ⁿ - xⁿ ] / (Δx)   Δx → 0

And by the binomial theorem, we can write

lim          [ xⁿ + C(n, 1)x^n-1 Δx + C(n,2) x^n-2 Δx² + ..... +C(n, n-1) xΔx^n-1 + C(n, n)Δxⁿ  - xⁿ ] / (Δx) 

Δx → 0

lim          [C(n,1) x^n-1 Δx + C(n,2)x^n-2 Δx² + ..... +C(n, n-1) xΔx^n-1 +C(n, n) Δxⁿ ] / (Δx)      

Δx → 0   

.... factor out Δx in the numerator...    

lim         (Δx) [C(n, 1) x^n-1  +C(n, 2) x^n-2 Δx + ..... +C(n, n-1) xΔx^n-2 +C (n, n) Δx^n-1 ] / (Δx)

Δx → 0

lim          [C(n, 1) x^n-1  + C(n, 2) x^n-2 Δx + ..... +C(n, n-1) xΔx^n-2 + C(n, n) Δx^n-1 ]

Δx → 0

And taking the limit as Δx → 0 we have

C(n,1) x ^n-1   ..........  but   C(n, 1) is just n......so we have......

nx^n-1

1 mole of NaHCO3 is 84.007g, so to find how many moles .006 is, divide 84.007 by .006, which gives you 0.00007 moles.

I think it just meant to use (x) as a number, so just x+3, where x can represent any number 

so 5d-9=24 is a simple algebraic problem, and the goal of this problem is to isolate the variable (d) so that we can find out what d is. So in this problem, the first thing we can do to isolate d would be to get rid of the -9, so in 5d-9, to get rid of the 9, we would add a 9, and then we would also add a 9 to the right side, because anything we do to one side of the equation must be done to the oter side. So after we add 9 to both sides of the equation, we get 5d=-15. Then we want to get rid of the coefficient on the d, so we divide both sides by 5, this removes the 5 from the d, making it d=-3. and thats your answer, d=-3. Hope this helps, if you are confused just ask. :)

h(10) cannot be reduced or solved further, if it is a function of h, e.g. h(10)=h+5, then we can say that h(10) would equal 15, but h(10) is not answerable or reducable.

Add 81 to 153. Ignore the negatives for a while.

$${\mathtt{81}}{\mathtt{\,\small\textbf+\,}}{\mathtt{153}} = {\mathtt{234}}$$

Now, put the negative behind the 234.

$$-234$$

So, $$-234$$ Is our answer

You can look up here.

On what, my friend?

In algebra, we're often asked to solve for x, and, in the English language, the letter x is often used to signify the unknown—X marks the spot, X-rays, and Mr. X, for example. But how did this particular letter become associated with so much mystery? In the 2012 TED Talk above, Terry Moore traces the use of the letter x in algebra to the Arabic word al-shalan, which means "the unknown thing," claiming that, in translations of the writing of Arabic mathematicians, that word became linked to the Greek letter chi and then reached us through Latin and, eventually, Spanish. It's a neat story—and a similar explanation even appears in Noah Webster's Dictionary—but is it true? In fact, the use of x (as well as y and z) became common thanks to René Descartes' use of the last three letters of the alphabet to represent unknown quantities in his treatise La Géométrie. In his classic study A History of Mathematical Notations, Florian Cajori says that there is no historical evidence for the Arabic connection to Descartes' use of x, and, in fact, lists a number of other stories associated with the letter: Some writers have claimed that Descartes' printer wanted to use x as the unknown quantity because the letter appears relatively infrequently in French and Latin, making it convenient for typesetting. (However, Descartes used x as an unknown long before the book was typeset, although some writers have wondered if this accounts for x's eventual predominance over y and z.) Others have noted the similarities between the letter x and the common German mathematical symbol for the unknown, and have proposed that Descartes rendered that German symbol as an x. (Descartes actually uses that symbol alongside x.) Yet another hypothesis proposed that the x was a crossed numeral 1, based on Cataldi's notation of the first power of the unknown.

help mmmeeeee

On the website calculator specifically, you can press "Enter" again to get the answer in scientific form (the number times 10 to a power).

Thank you. But I quite think it's that one... But thank you! It helped a whole bunch!

Harvard claims this is the hardest math class in the country

en.wikipedia.org/wiki/Math_55

We have 6 "faces"......with three different rectangular areas being  "doubled"...so we have.......

2 [ (2x * 3x) + (2x * 5x) + (3x * 5x)] = 

2 [ 6x² +  10x² + 15x² ] =

2 [ 31x² ] =

62x²

By learning it in school. It is easy to learn at school. 

I don't see any n. Please include information.

We can set this up as a proprtion and solve

(2+2/5)hrs/ 15miles = x hrs /  2miles        ...... cross-multiply

2(2 + 2/5) = 15x    ..........divide both sides by 15

2(2 + 2/5)/15 = x  = .32 hrs  .....      and to find the minutes, multiply this by 60....so....  .32(60) = 19.2 minutes to run 2 miles

Maybe they drew a circle.

Uh-oh, that question isn't objective. All you need to do is make x smaller than 1/3 of y.

And thinking and human society (not everyone knows numbers).

What happened? We can help if you tell us.

So, can I use any number?

if yes, here it is!

$$52+3+a$$

I think that is an algebraic expression.

hope that this helps!