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negative 4 to the power of 3 = -64

user zmason

pswrd twcody 

associative

69-69=0 it is 0   

If wasserpark is maskulin then the article we'll use is der so der wasserpark.

der wasserpark

it is maskulin. 

the answer is ZERO(0)

If u tell me the exact meaning if wasserpark in English then maybe I can tell u the article used for it!btw is this article Dativ,Nominativ or Akusative and is it feminine, maskulin, neutrum or plural ? If your a German student u might be knowing what am asking for ! 

Oh that's what I did but I just made a slight mistake , I devided it not by 80 but 30, so anyways thanks for all the help!i must give u some points ! Thank you !

Because the original cost of a single article is Rs 30.  

The question asks for the selling price of a single article.

You could have taken 16% of Rs 2400, added this to Rs 2400 to find the selling price of all 80 articles, but you would then have to divide the result by 80 to find the selling price of a single article.

Hopefully, you would get the same result!

Incidentally, I didn't divide 16% by 100; I divided 16 by 100.  16% means 16 divided by 100.

The answer's 20!!!

Alan why did u divide 16% by 100 and multiply by 30?if it says that the profit is 16% so why r we taking out 16% of 30?

$${\sqrt{{\mathtt{328.29}}}} = {\mathtt{18.118\: \!774\: \!793\: \!015\: \!117\: \!1}}$$

To 3 significant figures this is 18.1

(Don't confuse this with 3 decimal places which would be 18.119)

The original price of one article is Rs 2400/80 = Rs 30.

16% of Rs 30 is Rs (16/100)*30 = Rs 4.8

So the shopkeeper must have sold each article for the price originally paid plus the profit on each one, namely

Rs 30 + Rs 4.8  =  Rs 34.8

We can show that Chris's solution is the only one as follows:

Treat this as a quadratic in a:  a² - (b+c)a +b²+c²-bc = 0

Solve for a using the quadratic formula

a = (b + c ± [(b+c)² - 4(b² + c² - bc)]^1/2)/2

a = (b+c ± [b² + c² + 2bc - 4b² - 4c² +4bc]^1/2)/2

a = (b+c ± [6bc - 3b² - 3c²]^1/2)/2

a = (b+c ± [-3(b - c)²]^1/2)/2

a = (b+c ± i*(b-c)*√3)/2

This can only be real (presumably the triangle has real sides!) if b = c so that the imaginary part vanishes.

When  b = c then a = (b + c)/2 = (b + b)/2 = b

So all the sides are the same length.

Oh okay! Thank you Alan, I've understood everything now! I shall give u some points for your helpful answers! Thank you !

You are asked for the decrease in numbers (which is 676) to be expressed as a percentage of the original (i.e. Sunday's) number (which is 845), so you must have decrease/original. Then you simply turn this fraction into a percentage by multiplying it by 100.

Alan I just don't get one thing, why are we dividing 676 by 845 and making a fraction as 676/845 ? That's only what I have a doubt on !

What do you mean?

From the second of these we have x = 2y - 15  (by adding 2y to both sides).

Replace x in the first equation by 2y - 15

3y -4(2y - 15) = 40

3y - 8y +60 = 40

-5y + 60 = 40

Add 5y to both sides

60 = 40 + 5y

Subtract 40 from both sides

20 = 5y

Divide both sides by 5

y = 4

Using the fact that x = 2y - 15 we have 

x = 2*4 - 15

x = -7

The decrease in the visitor numbers on Monday = 845 - 169 =  676

This as a fraction of the number on Sunday is 676/845

To find this as a percentage just multiply by 100, so the percentage decrease is 100*676/845 = 80%

No. It's about writing and s**t...

In this we have same denominators so we don't have to do much but just add the numerators which is 5 and 5 and it gives us 10 so our answer is!

5/12 + 5/12

= 10/12     ( and now we will reduce them)

= 5/6    ANSWER

So that easy it was!

If the angle is A then its supplement is 180° - A.

180 - A = 8A

Add A to both sides

180 = 9A

Divide both sides by 9

A = 20°