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i need help with the answer what is it?

Hi IMB   (I am bad ... )

Welcome to the Web2.0calc forum!

Give yourself a point  

Sorry man, I guess it's overdue now..........

Find all possible values of a, if the equations ax^2+5x+1=4x^2+7x-4 has two different real roots

Hello Guest!

\(ax^2+5x+1=4x^2+7x-4\\ ax^2-4x^2+5x-7x+1+4=0\\ (a-4)x^2-2x+5=0\)

\(a\in\mathbb R\ |\)  \(-\infty\)  \(<\)  \(a\)  \(<\ 4.2\)  \(and\) \(\ a\neq 4\)

With \(a\in\{4,4.2\}\), the equations have only one real root.

  !

1, 2, 2, 3, 3, 4 ==6 digits

6! / [2!2!] ==180 - number of possible sequences of rolls.

H=5; M=15; A=abs((30*H) - (5.5*M))== 67.5 Degrees

Firstly, a number is invertible mod n if and only if it’s relatively prime to n. So the numbers that are invertible mod 2^n are just the odd numbers. k=2^n−1, so 2k=2^n.

Substituting that into your equation means 2k≡8 mod 13. Since 2 is relatively prime to 13, it is invertible, so we can divide it off to get k≡4 mod 13.

You don't have to use 6, 5 minutes, but still works

My answer to this is

You know there is 60 minutes in a hour, so for this question the answer will be 12:??

Then, after we find how much minutes left when it is 12:00, there is 25 more mintues. We add on 25, so 12:25

I am not the best at explaining, and I don't explain very much(new user and look at my username), so don't go attacking me. (I also skip like a lot of "simple" to me steps)

First, you can factor z^4 - 4z^2 + 4 = 0 into (z^2 -2)^2

I am assuming that you already know this, but i will still "explain"

You can turn z^4 - 4z^2 +4 = 0 into z^4 - 2z^2 - 2z^2 + 4

Then, you notice that you can factor that into z^2(z^2 - 2) -2(z^2 - 2)

Then, you can turn that into (z^2 -2)(z^2-2). Or, (z^2 - 2)^2.

You notice that \(\sqrt{2}\), will work, and -\(\sqrt{2}\). 

Because, \((\sqrt{2})^2\)is equal to 0, (2-2)^2 = 0

And \((-\sqrt{2})^2\)is also equal to 2.

I hope this helped?

If it's 11:55 and you want to find the time in +30mins. 30mins/6=5mins, so you can add 5 mins to 11:55, 6 times. After 1 time, 12:00, after 2, 12:05, after 3, 12:10, after 4, 12:15, after 5, 12:20, after 6,12:25. So in 30mins it will be 12:25. 

a + 6 = b-6 = 6c       sooo  a = b-12        c = 1/6 a   =  1/6(b-12)

a      + b       + c = 99

b-12   +  b     +  1/6 (b-12)    = 99

b= 52.153846                                            a = 40.153846                    c = 6.69231

The answer is 68, but I don't know how to get to there. 

When I did it out, I got 44. 

the extent people will go to advertise something...

72/4 = 18 years to get to 5400 

since 5400*2=10800 

18 * 2 = 36 years to get to 10800

Find slope , m      ( -3-5) /(2-4) = 4

point slope form

(y-5) = 4 (x-4)      re arrange

y-5 = 4x - 16

-4x+y = -11    

(7 * 6!)/ 6! = 7

x = 7

Thank you so much, I've been struggling on this question for a while, but I understand now @Alan!!! 

Thanks. Maybe our professor overlooked the problem :))

Thanks  for the confirmation Tiggsy.  

And thanks guest asker for interacting so nicely :)

Drat, I typed something in and somehow it got lost.

Here's the gist of it.

It often helps to list all of the possible outcomes with their associated probabilities, their sum should equal 1.

If it does, you can be reasonably sure that you haven't missed anything.

So, we have

O, O    = 3/10 * 2/10 = 6/100,

O, N    = 3/10 * 7/10 = 21/100,

O, S    = 3/10 * 1/10 = 3/100,

N, O    = 7/10 * 3/10 = 21/100,

N, N    = 7/10 * 6/10 = 42/100,

N, S    = 7/10 * 1/10 = 7/100.

                    Total     = 100/100,  tick.

The probability that the second coin is an old Peso is 6/100 + 21/100 = 27/100.

If we disagree somewhere then at least we should be able to see where the disagreement is.

Like this perhaps:

No Melody I'm with you, 27/100.

Ahr Tiggsy is answering.  He must have seen something that i overlooked.