All Answers 356072 Answers

Please let me know if it is correct or not

The shortest stick must be between 0 and 5/3.  The probability that it is longer than 3 is, therefore:

(5/3 − 3) / (5/3 − 0)

(-4/3) / (5/3)

-4/5

So the probability that both of the shortest sticks are longer than 3 is (-4/5)² = 16/25.

I actually don't really know how to solve this one so I used this https://brainly.com/question/17139544 as a reference.

Hopefully, it is correct

-Vinculum

The shortest stick must be between 0 and 5/3.  The probability that it is longer than 3 is, therefore:

(5/3 − 3) / (5/3 − 0)

(-4/3) / (5/3)

-4/5

So the probability that both of the shortest sticks are longer than 3 is (-4/5)² = 16/25.

I actually don't really know how to solve this one so I used this https://brainly.com/question/17139544 as a reference.

Hopefully, it is correct

-Vinculum

No, our answers are the same... I just did mine in decimal, and Chris did his in fraction form.

The shortest stick must be between 0 and 5/3.  The probability that it is longer than 3 is, therefore:

(5/3 − 3) / (5/3 − 0)

(-4/3) / (5/3)

-4/5

So the probability that both of the shortest sticks are longer than 3 is (-4/5)² = 16/25.

I actually don't really know how to solve this one so I used this https://brainly.com/question/17139544 as a reference.

Hopefully, it is correct

-Vinculum

you tell me... are the answers the same or different?

Because the lines are perpendicular, the other line has a slope of \(5\).

This means that the equation is \(y = 5x + b\)

Plugging in the point (8, 3), we get: \(3= 40+b\), meaning \(b = -37\)

Now, we have to convert \(y = 5x - 37\) into standard form. 

Subtracting \(5x\) from both sides, we get \(-5x + y = -37\)

Multiplying the equation by \(-{16 \over 5}\) , we get: \(16x-3.2y=118.4\)

From here, we can find the pair to be \(\color{brown}\boxed{(-3.2, 118.4)}\)

We can write  the first line as

y  =  (-1/5)x + 23/5     Note that the slope  =  -1/5

If the second ine is perpendicular to this one, then it will have a slope of 5

So we have  that

16x + Py  = Q

Py = -16x + Q

y = (-16/P ) + Q/P

This  means  that    -16/P  = 5    so   P =  -16/5

And since   (8,3)  is on this line then

16 (8) + (-16/5)(3)  =Q

128 - 48/5  = Q

592/5  = Q

So   (P, Q)  = (-16/5, 592/5)

That is for a different question

oh c**p didnt realise

Slope of first line = - 1/5    perpindicular is = 5

16x + py = q        slope =   -16/p = 5    p = - 16/5

16 x - 16/5 p = q       sub in the point (8,3) to find the value of Q = 118.4

I don't think you can apply the quadratic formula to get question one.

1 and 2)

Using the Rational root theorem

\(\left(x-3\right)\frac{x^3+2x^2-17x+6}{x-3}\)

\(\frac{x^3+2x^2-17x+6}{x-3} = x^2+5x-2\)

\(\left(x-3\right)\left(x^2+5x-2\right)\)

3)

 \(0^3+0x^2-17\cdot \:0+6=6\)

-Vinculum

Here: https://web2.0calc.com/questions/help_84215

actually its wrong

thats wrong.

thanks

wow...