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In geometry and trigonometry, 'r' usually represents 'radius'.

In statistics, it can represent rank, rank correlation, random number.

what was the question?

CPill's answer is far more complete than mine, with exactly the correct procedure. But, in the problem, he transposed 2014 into 2104, so check the last two numbers. 

OMG!! This is so beautiful! It makes me want to cry.

I do truly hope you are still a living Ghost!

Rosala, the Ghost posted a message for you. Don’t you remember?

I know zippo about biology, but it's enzyme "x.'   Note that it's active in colder temps, but the activity starts slowing at temps above about 30 degrees, or so.  Enzyme "y' is active all temps > 0 , but particularly in "hotter" temps !!!

Arithmetic...we're just subtracting 5 from the previous term to get the next term !!!

It would have 12......to see why....note that there are 10 multiples of 5 in 50! that could be paired with 10 even numbers in the product of 50! to produce a "0"  with each pairing. But 25 and 50 each have an additional factor of  "5" that could be paired with two other even numbers in the product of 50! ......so that gives us 12 trailing zeroes.

Note that there are 25 pairs of even numbers in the product of 50!, so we will be guaranteed to be able to pair twelve "5's with any twelve of them to produce 12 trailing zeroes.....!!!!

I dont think so... the compound for glucose is C6H12O6

99*7=693 thats the answer 

My way of looking at this is:

every number that ends in a 2 multiplied by a number ending in a 5 adds one more zero to the number of zeroes;

also multiplying by a number that ends in a zero adds another zero.

This means that 10! has two zeroes because it has 2 x 5 x 10; one zero for the 2 x 5 and another zero for the 10.

But this means: 1 through 10 adds 2 zeroes; so does 11 through 20; 21 through 30; up through 91 through 100 

for a total of 20 zeros

But I forgot about 25, since it contains 2 5's as factors, it will add 2 zeros not just one (there are a lot of extra 2's in the other numbers); so here is an extra zero.

Then, there is also, 50, 75, and 100; here are three more zeros.

OK, that's how you can get 24 zeros in 100!.

Can you use this to finish the analysis for 2014! ?

Here's the proceedure for finding the answer

• Take the number that you've been given the factorial of.
• Divide by 5; if you get a decimal, truncate to a whole number.
• Divide by 5² = 25; if you get a decimal, truncate to a whole number.
• Divide by 5³ = 125; if you get a decimal, truncate to a whole number.
• Continue with ever-higher powers of 5, until your division results in a number less than 1. Once the division is less than 1, stop.
• Sum all the whole numbers you got in your divisions. This is the number of trailing zeroes.

So we have

2014 / 5 = 402.8 = 402

2014 / 5² = 80.56 = 80

2014 / 5³ =  16.112 = 16

2014 / 5⁴ = 3.2224 = 3

2014 / 5⁵ =  .644   and we can stop

So...summing   402 + 80 + 16 + 3   we have   501 trailing zeroes

The max depth of the water is 24.5 ft.

45minutes=3/4 of one hour.

60km=3/4 of 80 km.

I think the answer is 60km.

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93/100

(2/3) to the second power is  (2/3)²  =  (2/3)·(2/3)  =  4/9

2 1/3 as a common fraction is  (2 x 3 + 1) / 3  =  7/3

3/4 x (7/3)  =  (3 x 7) / (4 x 3)  =  21 / 12  =  -7/4     [reduced]

Putting all these together:  4/9 - 7/4   =   4/9 + 7/4

The common denominator is 36            =  16/36 - 63/36   =  -47/36

2x - 2/x² - 2x + 1   =   x + 2/x² + 4x + 4

Simplifying the left side:  2x - 2x  = 0.

Simplifying the right side:  x + 4x  =  5x

- 2/x² + 1  =  2/x² + 5x + 4

Further simplifying:

             0  =  4/x² + 5x + 3

Multiplying both sides by x²:     0  =  4 + 5x³ + 3x²

This will have a solution, you can approximate it by graphing:  y  =  5x³ + 3x² + 4.

[And, like the quadratic equation, there is a cubic equation, but it's not simple.]