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Clap clap super dum members L you got it incorrect *slap $\displaystyle \begin{pmatrix} Lol & lol & lol \\ Lol&Lol&lol \\ beach&beach&beach \end{pmatrix}$

$your \ face \ HAH \ LOL \ GET \ IT$

If you answered 18 questions like that, then why did you not know where to begin for the question you posted? You are full of b******t or lying, which, in this case is just a petrified form of b******t.

Fine ill rephrase it, This is the 19th question i did Incorrectly. And since I dont want to fail, im asking for help. And Pardon me for being unreasonably rude But how do I know im not talking to a high-school dropout? Or a person who doesnt know squat about math besides what Google feeds him. Im averging a 95 in calculus rn. This is a new concept that id like some help with. Sheesh. 

How dare I ask a Chemistry Problem when theres literally people asking for simple division problems, fractions, addition. Those people dont get condemed. hmmm... Seems that you just targeted me. 

I supose, But this forum was approved by my teacher. Google was not. Dont wanna get in trouble.

OMG! You are a male version of a classic Goody Two-shoes.  LMAO!

 As for reporting me, by all means, report away.

All of the moderators and (probably) the administrator will instantly recognize who I am. (Melody, of course, already has.)

I supose, But this forum was approved by my teacher. Google was not. Dont wanna get in trouble.

Thanks for your answer Vinculum.    

Guest answerer clearly got out of bed on the wrong side today and I am not condoning his/her aggressive words.

But the suggestion to  "Google how to calculate hydronium ions" was most likely a good one.

If you learn to look things up on the net you can usually get more comprehensive answers and sometimes you learn more.

Often it is just knowing what words to use to get the answer you want that is the hard bit and guest has given you a good suggestion.

As for saying that googling is cheating, when you are here looking for an exact answer, that was a rather crazy thing to say.

i will have you know that the question was the 19th question like that

If you answered 18 questions like that, then why did you not know where to begin for the question you posted? You are full of bullshit or lying, which, in this case is just a petrified form of bullshit.

I did look at your posts, including your bullshit comments and suggestions.  None of your questions are calculus questions nor do any require calculus solutions.  One of your latest questions is an augmented proportion rate question – requiring basic seventh grade math skills to solve, and CPhill had to chew it up and feed it to you before you understood it.  You have one basic chemistry question –generally seen in grade 10 or 11. 

Your posted questions range from the seventh to the eleventh grade, but they are not are not in a progressive order. Are you trying to learn ahead? That’s fine, but it’s very irritating to answer a math question from students who are two or more prerequisites behind, especially when the student is too lazy to review and (re)learn the prerequisites

You dont have to be hostile about it

I may not have to be hostile about it, but dumb and lazy are great catalysts for this attitude and behavior –especially when they occur simultaneously.

GA

--. .-

Thank you so much! 

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\(8\) sides, \(70\)

Suppose Ben had \(b\) coins originally. Then Skylar has \(3b/5\) coins (also originally).

Since after Ben gives Skylar ten coins they each have the same amount, we can get the equation

\(b-10=3b/5+10\)

Solving, we have \(b=50\), so then Skylar had \(30\) coins. Therefore, the two friends had \(\boxed{80}\) coins altogether.

$4   is 1/2 of his remaining money

So......  4 / (1/2) =  $8  =   1/2 of his paycheck

So....his whole paycheck  =   8 /  (1/2)  =   $16

Find the slope   [   5 - 11 ] / [ -4 - 1 ]  =  -6 / -5   =  6 / 5

Write the equation of the line in point-slope

y = ( 6 /5) ( x - 1) + 11

y = (6/5)x - 6/5  + 11

y = (6/5)x  - 6/5 + 55/5

y = (6/5)x + 49/5        multiply both sides by  5/49

(5 / 49)y =   (6 /49)x  + 1

- (6 / 49)x  + ( 5/49) y  =  1

And we can write  this as

x / ( - 49/6)  + y / (49 / 5)   =  1

a =  -49 /  6

I mean, I have no clue what the heck that is, but it looks like math, and you just found a very rude user. 

You were right, and you handled it very well 

Your 6^4 ==1,296 is correct. That is called the "sample space". This 1,296 counts ALL the permutations possible in tossing 4 dice. The permutations will start at: 1111 and end in: 6666. The two examples you gave are already included in 1,296 permutations. They start like this:

1111 , 1112 , 1113 , 1114 , 1115 , 1116 , 1121 , 1122 , 1123 , 1124 , 1125 , 1126 , 1131 , 1132 , 1133 , 1134 , 1135.........  6651 , 6652 , 6653 , 6654 , 6655 , 6656 , 6661 , 6662 , 6663 , 6664 , 6665 , 6666 , Total =  1296 permutations.

x^2 - 1  = (x + 1)  ( x - 1)

Multiplying both sides by the right side above

- 9x  =  2 (x - 1) - 6(x + 1)  + 3(x - 1)      simplify

-9x = 2x - 2  -6x - 6 + 3x  - 3

-9x =  -x -  11

-8x =  11

x =   -11 /  8

The "2x"     compresses f(x)  horizontally  by a factor of 2

So.....the interval width  =   [ 9 - - 1 ]  / 2  =   10 / 2  =   5

Vowels   A , E , O , U

Consonants   D M  P  S

Choose  any 1 of the 4 vowels  = C(4,1) =  4

Choose any 2 of the 4 consonants  and  permute them in 2 ways =   P (4,2)  =  12

Total arrangements =   4 * 12   =    48

I assume this is

9^y =  3^( 5*9 / 27)

(3^2)^y = 3^(45/27)

3^(2y)  = 3^(5/3)          solve for the exponents

2y =  5/3      multiply both sides by 1/2

y = (5/3)(1/2) =  5/6