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Make certain that your calculator is in degree mode.

To solve a tangent problem, use invTan  or (2nd) tan

tan θ  =  -4        --->        θ   =  invTan( -4 )        --->         θ  =  -76.0°

But this answer isn't in your range of values.

However, tan has a period of 180°, so you can add or subtract 180° as many times as you like:

adding 180° to -76.0°, the answer becomes 104°.

I hope this helps!

[ (30 * 1000) + (3x100) - (90 + 1028) ] * 3

Work from the inside out:

[ (30000) + (300) - (1118) ] * 3

Finish the inside:

[ 29182 ] * 3

  =  87546

If you let 'n' to represent a number then '-9 times a number' can be written as -9n

'less then' means subtraction:  12 less then -9 times a number  becomes -9n - 12 (the subtraction in the equation is written in the opposite way as written in words)

'8 minus 4 times the number ' becomes 8 - 4n

So, the equation is:  -9n - 12  =  8 - 4n

Get all the variables to one side. If you add  9n  to both sides:

    -9n + 9n - 12  =  8 - 4n + 9n

    -12  =  8 + 5n

Subtract 8 from both sides:

    -12 - 8  =  8 - 8 + 5n

    -20  =  5n

Divide both sides by 5:

    -20 ÷ 5  =  5n ÷ 5

    -4  =  n

Now, check the answer:   -9n - 12  =  8 - 4n

               -9(-4) - 12  =  36 - 12  = 24                 8 - 4(-4)  =  8 + 16  = 24        They check!

EE means to enter something in scientific notation.

To enter 23 x 10^15 on a calculator enter as 23 EE 15.

Is there a difference between x and X?

What is the problem?

16n - 2 > 8n + 62

Subtract 8n from both sides:

16n - 8n - 2 > 8n - 8n + 62

8n - 2 > 62

Add 2 to both sides:

8n - 2 + 2 > 62 + 2

8n > 64

Divide both sides by 8:

8n ÷ 8 > 64 ÷ 8

n > 8

30000+3x+10000-1118

Solving  4x - 3  =  21:

[Add 3 to both sides]     4x - 3 + 3  =  21 + 3

[Simplify]                                4x  =  24

[Divide both sides by 4]             x  =  6

Now, for the second part:  do you mean (x - 2)2         or do you mean  (x - 2)²

 (x - 2)2  =>  (6-2)2  =>  (4)2  => 8

 (x - 2)²  =>  (6 - 2)²  =>  (4)²  =>  16  

The first term as a variable, the second doesn't so there isn't any variable that can be factored out.

The first number is  15  =  5 x 3

The second number is  27  =  3 x 3 x 3

There is one common factor,  3.

The greatest common factor of  15x  and  27  is 3.

The only number that can be factored out of  15x + 27  is  3;   3(5x + 9) 

if its an iphone take ur charger cord plug it into your computer and ur phone then a apple thing will show up then sync the phone to the computer make all the notes into a file then print the notes and wala this should work but things may have changed scince i switched to samsung so that is the only way i know tell me if it works

1001  can be factored into  7 x 11 X 13

So,  .1 x 1 x 7 x 11 x 13  =  100.1

Which value you choose for which letter determines the various answers.

To round to 4 significant places, you will round to the fourth digit from the left (except as shown below) 

look at the fifth digit from the left, if it is 5 or larger, round the fourth digit up one; if it is 4 or less, don't change the fourth digit. Since it is a  7  round the fourth digit to  5.

Answer:  18.35

The above rule will not work if the number is less than 1; that is, if it only a decimal.

For instance, if the number were 0.0018347, then you round to the fourth digit from the first non-zero number, giving an answer of 0.001835. (If the number starts with zeros, don't count those zeros.)

If you subtract  -9  from  40, you have:  40 - -9

But sutracting a negative is the same as adding a positive, so  40 - -9  =  40 + 9  =  49

If the whole expression  1 + 5x  is under the square root sign:

          1 + x  =  √(1 + 5x)

Remove the square root sign by squaring both sides:

          ( 1 + x )²  =  ( √(1 + 5x )²

      1 + 2x + x²   =   1 + 5x

Subtract 1 + 5x from both sides and rearranging:

              x² - 3x  =  0

        x ( x - 3 )  =  0

So  x = 0  or  x = 3

But these are only possibilities! They must be checked!

         1 + 0  =  √(1 + 5·0)     --->   1  =  √1      Yes!

         1 + 3  =  √(1 + 5·3)      --->  4  =  √(16)  =  4     Yes!

So, both  0  and  3  work.

1 + x = √(1 + 5x)   square both sides

1 + 2x + x ^2   = 1 + 5x     subtract 1 + 5x from both sides

-3x + x^2  = 0     rearrange

x^2 - 3x = 0        factor

x (x - 3)     and setting each factor to 0, we get that  x = 3  or x = 0

Make sure to check these answers....square root equations of this sort often give "extraneous" answers  that will not work in the original problem......here, we're OK though !!!

-5+5-(-6)=6

Either we have

[1-(-49) / 81 =

50/81

Or we have

1 - (-49/81) =

1 + (49/81) =

[81 + 49] / 81 =

130/ 81

If the problem is:  1 - -49/81, the problem can be simplified because                                                                                                                      subtracting a negative can be replaced by adding a positive:

                           1 + 49/81  =  1 49/81.

If the problem is:  (1 - -49) / 81,  then it reduces to  (1 + 49)/81  that is  50/81.

I'm not sure exactly what you mean, but I'll take a stab at this:

If you want to simplify  √(4/9)  

write it as the square root of the numerator divided by the square root of the denominator, as:

    √(4/9)  =  √4 / √9  =  2/3

Also:  √(17/36)  =  √17 / √36  =  √17 / 6

If this doesn't answer your question, post back and include some problems. Thanks.

Let  n  =  50.8383838383838 ...

Since the number of digits that repeat is two multiply the both sides by 100 and subtract the original equation from the new equation:

   100 n  =  5083.838383838383 ...

      -   n  =     50.838383838383 ...

   -------  =  ---------------------------

     99 n  =  5033                      (Everything after the decimal point subtracts out.)

-->    n  =  5033/99

If only one digit repeated, multiply by 10; if three digits repeated, multiply by 1000; etc.

Since  cot(x)  =  cos(x)/sin(x),  the  cot(x)  will be undefined whenever  sin(x) = 0  and these are the locations of the asmyptotes of the function. 

sin(x) = 0  at  0  radians,  ± π radians,  ± 2π  radians,  ...