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23 * 158 =

3634 =

16  =

7

80mi / 65mi/hr =   16/13 hrs

(16 /13) * 60 min  ≈  73.85 min ≈  74 min =   1hr 14 min after 10:32 AM  =

11:46 AM

F     8     D

      15

A             I

Min possible distance =  sqrt [ 15^2 - 8^2 ]  = sqrt[ 225 - 64 ] = sqrt [ 161] ≈ 12.69 m

2x + 5     must   = 1    .....so

2x = 1 - 5

2x = -4

x = - 2  .... so

3(-2) + 9 = 

3

You are very welcome Nerdiest :)

Great,

It is always good to get feedback.  :)

Thanks Voldemort, that makes sense.

a ==5b..............(1)

a + b ==18........(2), solve for a, b

From (2) above:

a ==18 - b

Sub this in (1) above:

18 - b ==5b

18 ==5b + b==6b

b==18 / 6 ==3

a ==18 - 3 == 15

a * b ==3 * 15 ==45

I think there is a mistake in your question! I think 8 should be 9. If that is so, then:

Let the total number of students ==S

S - 1/3S ==2/3S

3/4 * 2/3S ==9

1/2S ==9

S ==9 * 2 ==18 - total number of students in Mr. Short's class.

Let the length = x  and the width x - 60

perimeter =  2x + 2 (x - 60)  = 500

2x + 2x - 120  = 500

4x  = 500 + 120

4x   = 620

x =  620 / 4  =   155

x - 60  = 155 - 60  =   95

Area = 155 * 95  =  14725 ft^2

THANK YOU VERY MUCH MELODY AND GUEST, for I got the first insanely hard, than easy understanding question RIGHT!

THANK YOU

THANK YOU

THANK YOU

345,600  =

3456 x 100  =

576 x 6 x 100 =

24^2 x 2 x 3 x 10^2 =

6^2 x 4^2 x 2 x 3 x 2^2 x 5^2  =

2^2 x 3^2 x 2^4  x 2 x 3 x 2^2 x 5^2=

2^9 * 3^3 * 5^2

abc  = 9 * 3 * 2  =   54

arctan x + arctan y =   pi / 4

This will be true  when either

x  = 0   and y = 1

or

x = 1  and  y = 0

So

xy + x + y =   1

Let total weight of grapes==10 kg
8kg==weight of water
2kg ==weight of pulp

2 + w ==4
w ==2 kg - weight of water after evaporation.
8 - 2 ==6 kg in water loss
6/8 ==75% - total loss of water.

2 / 4 ==50% weight of water as a percentage of grapes. 

Here : https://web2.0calc.com/questions/help-with-geometry_135

that's wrong

xy + x + y = sqrt(2).

\(m=\dfrac{y_2-y_1}{x_2-x_1}\)

Insert the coordinates.

  !

121 = 11^2

11^3 ==1,331 - smallest perfect cuble divisible by 121

Let the distance covered by Noah==D

The distance covered by Grady ==D + 15

Let Noah's speed ==S

Grady's speed ==1.6S

3S == D.........................(1)

3 * 1.6S ==D + 15..........(2), solve for S, D

D==25 miles - distance covered by Noah

S==8 + 1/3 mph - Noah's speed

See, the goal of this forum is for question askers(like you) to learn from answers(by us). 

Voldemort is trying to help you learn, so you won't have to ask for help next time. 

We are willing to help you and WILL help you if you can explain to us what you have tried. Our goal is to help you learn, and that can only be done with your co-operation...

That doesn't seem right?