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There are 2 possible values of x.

The distance is 2*sqrt(47).

         x    y

1 = (0, -5)
2 = (-3, -4)
3 = (3, -4)
4 = (-4, -3)
5 = (4, -3)
6 = (-5, 0)
7 = (5, 0)
8 = (-4, 3)
9 = (4, 3)
10 = (-3, 4)
11 = (3, 4)
12 = (0, 5)

Add up all the x values to the left.

Let the number ==N

N^3 ==3 * N^2  * 2

N^3 ==6 * N^2

Divide both sides by N^2

N == 6

a + b = -47.

The total amount of marbles: \(6+5+3=14\)

The probability that your first pick is red: \(\frac{6}{14}\)

The likelihood that the second pick is red: \(\frac{5}{13}\), remember you already picked a red one!

Multiply them together to get: \(\frac{6}{14}\cdot\frac{5}{13}=\frac{30}{182}\), and just simplify that yourself to get the answer!

I hope this helped!

If \(8 + t\) is the hypotenuse, we have the equation \((8 + t)^2 = (t + 1)^2 + (t - 1)^2\)

Solve for t, and use the positive, real values 

If \(t + 1\) is the hypotenuse, we have the equation \((1 + t)^2 = (t + 8)^2 + (t - 1)^2\)

Again, solve for t, and use positive, real values. 

If \(t - 1\) is the hypotenuse, we have the equation \((t - 1)^2 = (t + 8)^2 + (t + 1)^2\)

Solve for t, and use the real, positive values. 

Can you take it from here?

Probability = 6/(14) * 5/13

= 3/7 * 5/13

=15/91

Sqrt(10^37 / 0.1)==sqrt(10^38)==10^19

10^19 / 10^8 ==10^11

10^n ==10^11

n == 11

You might get other answers if you present your question properly.

Your question makes no sense

tie Fred Gwen and scott together in a line.  there are 3! arrangements for this 

Now put them in the circle, they determine the 'start' of the pattern

There are 3 more people which can be arranged in 3! ways

So the answer is  3!*3!

Answered here:

The lateral surface area tells us that \(2 \pi r \times h = {7 \over 2}\)

We also know that, from the volume, \(\pi r^2 \times h = {21 \over 2}\)

Now, just solve for r and h

how the heck do you have the time to answer so many questions lmao you answer so many 

See here :  https://web2.0calc.com/questions/need-help_80318

The table shows the prices of the tickets for a charity performance 

     Type of ticket     Price per ticket

           Adult             $20

           Child              $8

1/4 of the tickets sold were adults tickets. The total amount of money collected from the sale of child tickets was $216 more than the total amount collected from the sale of adult tickets. How much money was collected from the sale of the tickets altogether?

Let x be the total sold.....so  (1/4)x =  the adult's sold  and (3/4)x = the children's sold

So

Number of adult's sold * price per ticket + 216 =  Number of chidren's sold * price per ticket

(1/4)x * 20 + 216 =  (3/4)x * 8      simplify

5x + 216 = 6x

216 =  6x - 5x

216  =  x 

Total money collected =  (1/4) (216)*20  + (3/4)(216)* 8  =  

5(216)  + 6(216)  =  

11 (216)  =

$2376

Where is the pic?

See my answer under your original post.

Let Evan's erasers at first =  E

Let Robert's at first =  (5/6)E

When Evan gives (1/2) of his to Robert he has  (1/2)E left       and Robert has (5/6)E + (1/2)E

So

(1/2)E +  50 =  (5/6)E + (1/2)E

50 =(5/6)E

50 (6/5)  = E =   60    =  what Evan had at first

The points  (0,4) and (1,1)  are on  the line

The slope of the line  = (1-4) / (1 -0) =  -3/1  = -1

Using the point  (0,4)  and the slope the  inequality is  either

y  ≤ -3x + 4   or     y ≥ -3x + 4

Note that the point (2,2)  is  in the  feasible region  and it satisfies  the second inequality

So

y ≥ -3x + 4

3x + y  - 4 ≥  0