All Answers 358460 Answers

\(2x-7\over\sqrt{x^2-7x+6}\)

That means the denominator has to be Greater or Equal to 0.

(x-6)(x-1) = 0, x = 1 and 6 for values of 0. 

x^2 - 7x + 6 > 0 

(x - 6)(x - 1)>0, double neg or double pos.

x>6 and x<1

Domain: (-inf, 1] U [6, inf)

1/3 < M/30<5/3

Multiply by 30

10

M is from 11 - 49 inclusive, 49 - 11 + 1 = 39 integer values of M

The x coordinate can never reach the value of 3/2, but the y value can.

After some calculations, you'll see that when t = 25/18, it reaches 3/2. Then add 2 every time, so the second time it reaches will be at 61/18, then 97/18 then 133/18. 

\({25\over18}, {61\over18}, {97\over18}, {133\over18}\)

By the angle bisector theorem, BC/AB = CY/AY

BC/8 = 3/8

BC = 3

I don't understand.  Can you explain more?

Notice how a long of the terms share a denominator of a^3 + 7, so we can multiply every term in the equation by a^3 + 7.

1 - 7(a^3 + 7) = -a^3 + 5(a^3 + 7)

a^3 + 1 = 12(a^3 + 7)

a^3 + 1 = 12a^3 + 84

11a^3 = -83

a = cube root of -83/11

First, notice that it is a right triangle, so x and y could be 7. You want x to be as close to y as possible to get the shape as close to a square as possible (since it is the optimal area), thus x and y are 3, 4 so x + y = 7

\(1\over1+{1\over\sqrt{3}}+2\)

Multiply top and bottom by root3 and combine 1 + 2.

\(\sqrt{3}\over3\sqrt{3}+1\)

Multiply top and bottom by \(3\sqrt{3}-1\)

\(\sqrt{3}(3\sqrt{3}-1)\over(3\sqrt{3}+1)(3\sqrt{3}-1)\)

\(9 - \sqrt{3}\over26\)

Adding a negative number is parity: the minus sign is like a -1 x 58

The minus sign takes priority so +-58 = - 58.

Multiply everything by 5.

5/4 < x < 65/2

1.25

x = 2 to 32 which is 32 - 2  + 1 numbers = 31 integers

The smallest distance is 4*sqrt(2).

The indicates angle is 130 degrees.

Angle TUW = 48 degrees.

Mario received 4 dollars more.

q(-1) = 37.

m = 498.

cos ABM = sqrt(2)/2.

m = 782.

The answer is 45.

Looks like you'll need a numerical method to find the values: