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All numerators that are multiples of 3, from 3 to 2019 will express the fraction in lowest form:

[2019 -  3] / 3 + 1 ==673 fractions

@Cphil @melody pls help

Could you please explain your reasoning?

Solve by plugging in \(0\) for \(y\)

\(3(0)=-4x+24\)

\(0=-4x+24\)

Add \(4x\) to both sides.

\(4x=24\)

Divide both sides by \(4\).

\(x=6\)

Hence, the x-coordinate of the x-intercept is \(6\).

(The x-intercept itself is \((6,0)\)).

alpha = 70 degrees.

The smallest possible value of k is 2.

f(z) = 2z + 7.

Who's Mr.BB? Is it me?

If I am not dumb...

If radius is 13 yards, then diameter is 26 yards ;]

Simplify 2x^2 - 8x + 7 = x^2 - 5x + 3 and Solve for X

x^2 - 3x + 4 = 0

X is equal to (3 + or - isqrt7) / 2

\:\left(\frac{3}{2}+i\frac{\sqrt{7}}{2}\right)^{^{3\cdot \left(\frac{3}{2}-i\frac{\sqrt{7}}{2}\right)}}+\left(\frac{3}{2}+i\frac{\sqrt{7}}{2}\right)\left(\frac{3}{2}-i\frac{\sqrt{7}}{2}\right)^3

There are:

270 integers that are multiples of 5 and 8

There are:900 3-digit integers

Therefore, there are: 900 - 270 ==630 integers that neither multiples of 5 or 8.

Solve for X

X = 7 / 2

Plug X in (4x + 17) / (4x + 1)

The value of (4x + 17) / (4x + 1) is

31 / 15

FV ==6,000 x [1 + 0.04/12]^(3*12)

FV ==6,000 x [1 + 0.0033333]^36

FV ==6,000 x  1.1272718745179

FV==$6,763.63 - FV of 6,000 at 4% componded monthly for 3 years.

Try something like this:

1,000,343 ==1,000,000 + 343

[1,000,000 + 343]^(1/3) ==[100 + 7]==107 - since this is a prime number, then it must be one of the prime factors.

Then by simple long division: 1,000,343 / 107 ==9,349 - this must be the 2nd prime factor.

help

Without a calculator lol

I know, 107 and 9349, but like we don't have fancy calculators in math contests 

Also this is under the unit of factoring

And I kinda need work, not just an answer

But ty 

You could just use a calculator.

factor(1000343) = 107*9349

Owen made 45 shots.

Thank you!