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 Write its equation in vertex form.

Hello Guest!

vertex (0,-3)

P (-4,-5)

\(normal\ form\\ y=ax^2-3\\ -5=a\cdot16-3\\ a=-\dfrac{2}{16}\\ a=-\dfrac{1}{8}\\ \color{blue}f(x)=-\dfrac{1}{8}x^2-3\)

\( a=-\frac{1}{8}\\ d=0\\ e=-3\\ vertex\ form\\ f(x)=a(x−d)^2+e\\ \color{blue}f(x)=-\frac{1}{8}(x-0)^2-3\)

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I made a mistake,  here is the actual problem: A certain club has 50 people, and 10 members are running for president. Each club member either votes for one of the 10 candidates, or can abstain from voting. How many different possible vote totals are there?

Oh!  Here is the actual problem:  A certain club has 50 people, and 10 members are running for president. Each club member either votes for one of the 10 candidates, or can abstain from voting. How many different possible vote totals are there?

By the way, the (127) was supposed to be the bottom number, but the latex wouldn't allow more than one digit.

thank you i would have to ocouble check if that is right :)))

ok, the answer is either 1200 or 230300 (:

Hope I could help!

never mind I was given the wrong question to solve this one is slightly more complex but still doable haha

do you know combinations?

for this question you will use the combination formula which is

\(n!/r!(n-r)!\)

in this case your n is 50  and your r value is 4 because you have 50 options are you are choosing 4. 

When plugged into the formula this gives you 

\(50!/4!(50-4)!\)

simplified this is 

\(50!/4!(46)!\)

can you solve from here?

no they cannot abstain from voting

can the people abstain from voting?

yes it is still wrong :((

i appreciate your help :)

have you tried 4^50?

yes but it is wrong :(((

Hey actually this question was solved

Omg sorry here's the new question:

A certain club has 50 people, and 4 members are running for president. Each club member - including the members running for president - votes for one of the 4 candidates. Candidates may vote for themselves or for a different candidate. How many different possible vote totals are there?

This can be easily calculated this way. 

on both sides of the equation, there is a positive and a corresponding negative number. 

(75 and -75), (72 and -72), etc

So what this does is it cancels out all numbers as adding 75 to -75 will equal 0

so all numbers will cancel out their corresponding negative except for the two negatives with no corresponding number (-78 and -81)

So what it will leave you with is something much more simple to solve

-78+(-81)

Hope this helps!

Hi are there any numbers that go with this post? because with none it's unsolvable.

Here let me help 

First, let's cancel these out

3x + 2/x - 4 = 2(x + 9) - 2x + 7x + 3x + 2/x

      -2/x                                               -2/x

Now we have

3x - 4 = 2(x + 9) - 2x + 7x + 3x 

But wait there's still one more thing that will cancel out. 

3x - 4 = 2(x + 9) - 2x + 7x + 3x 

-3x                                      -3x

After this we have 

-4=2(x+9)-2x+7x

Now we multiply the numbers

Hope this helps!

-4=2x+18-2x+7x

Next, the -2x and the 2x cancel out leaving us with

-4=18+7x

Then we will subtract the 18 from both sides leaving us with

-22=7x

Finally, we divide by 7 getting us an answer of

-22/7=x

im deperate plesee

Hey! does >= mean greater than or equal to or did you add an equal sign accidentally?

Once you say I can help with the problem.