The probability is 2/35.
The smallest distance is 2*sqrt(10).
Angle DBA is 144 degrees.
The height is 10.6 inches.
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The mean is 120 degrees.
Where are the cards, and how many of them are there??
Angle DAC is 26 degrees.
a=10; c=109 % a; if(c==4, goto3, goto4);printa; a++;if(a<100, goto1, 0)
15, 21, 35
109 mod 15 ==4 - Remainder
109 mod 21 ==4 - Remainder
109 mod 35 ==4 - Remainder
Two-digit moduli ==15 + 21 + 35 ==71
thanks!!
Angle ABC ==180 - 124 ==56 degrees
Angle ACB ==180 - 56 - 95 ==29 degrees
You can find a useful answer here:
https://web2.0calc.com/questions/halp-please-geometry
Thank you so and very much for your timely and correct response. :)
a ==3b.......................(1) Angle b ==180 - a.......(2) Substitute a from (1) into (2) above: b ==180 - 3b Add 3b to both sides b + 3b ==180 - 3b + 3b The right-hand side: -3b + 3b ==0 b + 3b ==180 4b ==180 b ==180 / 4 b ==45 degrees a ==3b a ==3 x 45 ==135 degrees.
You don't see any NUMBERS missing from your question? Do you have problems with your vision?
The possible values of d are 14, 28, and 66, so the answer is 14 + 28 + 66 = 108.
The probability is 11/48, so the answer is 59.
That's not right but thanks
Could someone else help plase?
\(\frac{1}{\sqrt2}+\frac{3}{\sqrt{8}}+\frac{6}{\sqrt{32}}\\\\ \frac{1}{\sqrt2}+\frac{3}{2\sqrt{2}}+\frac{6}{4\sqrt{2}}\\\\ \frac{1}{\sqrt2}(1+\frac{3}{2}+\frac{6}{4})\\\\ \frac{\sqrt2}{2}4\\\\ 2\sqrt2 \)
Hi OldTimer
\((a+\sqrt b)(c+\sqrt d)\\ =ac+bd+a\sqrt d + c\sqrt b\\ \text{This will only be rational if, and only if, the last two terms cancel each other out ie}\\ a\sqrt d = -c\sqrt b\\ \text{which simplifies to}\\ \frac{c}{a}=-\frac{\sqrt d}{\sqrt b} \)
\(x = {1\over2 + {1\over x - 3}}\), multiply by (x - 3)/(x - 3)
\(x = {x - 3\over 2x - 6 + 1}\)
2x^2 - 5x = x - 3
2x^2 - 6x + 3 = 0
Quadratic formula!!!
