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I am sorry guest but your answer is incorrect, the solution to this question should be:

(a^3+3ab^2 = 679)+(a^3-3ab^2=673)=(2a^3=1352)

a^3=676, a=(676^(1/3))

(a^3+3ab^2=679)-(a^3+3ab^2=673)=(6ab^2=6), (ab^2=1)

(676^(1/3) )b^2=1, b^2=1/(676^(1/3))

b=1/(676^(1/6)) 

which means a-b=(676^(1/3))-1/(676^(1/6))

-Stereo 

The answer is 36

No bitches

I am scammer

Please show the sequence you are referring to. 
-Stereo 

Because at least three squares are red and it is a row of five squares you must have R,_,R,_,R

and the two blanks can be either yellow or blue. If you count it out you will get:

R,Y,R,Y,R

R,B,R,B,R

R,Y,R,B,R

R,B,R,Y,R

and you will get the answer 4 ways.

-Stereo 

Please show the sequence you are referring to. 
-Stereo 

Because the probability of being elected as president is equally likely and the probability for a sophomore to be elected is the same as the probability for a freshman to be elected, the answer should be 1/2 

-Stereo 

Let's denote the two points on the circle as A and B.

To find the probability that the distance between A and B is at most 1, we can start by drawing a diagram of the circle and marking a region where the distance between A and B is at most 1.

This region consists of all the points on the circle that are within a distance of 1 from each other. We can visualize this as two semicircles with radius 1 that intersect each other, as shown in the diagram below:

Let A and B be the two points that we choose at random. We want to find the probability that the distance between A and B is at most 1.

One way to approach this problem is to use geometric probability. The total area of the circle is πr^2, where r = 1 is the radius of the circle.

The area of the region where the distance between A and B is at most 1 is the area of the two intersecting semicircles.

To find this area, we can subtract the area of the two triangles ABA' and ABB' from the area of the two semicircles.

The area of each semicircle is 1/2 πr^2 = 1/2 π. The area of each triangle is 1/2 base x height, where the base is the chord AB and the height is the distance from the midpoint of AB to the center of the circle.

The chord AB has length 2 sinθ, where θ is the central angle between A and B. The midpoint of AB is the midpoint of the chord, which has a distance of sinθ from the center of the circle.

Therefore, the height of each triangle is sinθ, and the area of each triangle is 1/2 (2 sinθ)(sinθ) = sin^2 θ.

The area of the region where the distance between A and B is at most 1 is then:

2(1/2 π) - 2(sin^2 θ) = π - 2sin^2 θ

Now, we need to find the probability that the distance between A and B is at most 1. This is the ratio of the area of the region where the distance between A and B is at most 1 to the total area of the circle:

P(distance ≤ 1) = (π - 2sin^2 θ)/(π) = 1 - 2sin^2 θ/π

To find the probability, we need to integrate this expression over all possible values of θ from 0 to π.

∫[0, π] (1 - 2sin^2 θ/π) dθ

Using the identity ∫ sin^2 x dx = (1/2) (x - sin x cos x) we get

= 1 - 2/π ∫[0, π] sin^2 θ dθ = 1 - 2/π [π/2 - 1/2 sin(2π)] = 1 - 1/π

Therefore, the probability that the distance between two randomly chosen points on a circle of radius 1 is 1 - 1/pi.

4/63 or 0.0635 (decimal is rounded)

6 / (2/3) = 6 x (3/2) =18 / 2 =9

Was that difficult?

Why don't you try:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10=55

Average = 55 / 10 = 5.5

Median = [5 + 6] / 2 = 5.5

If 1/4 of the total paint used is white, then 3/4 of the total paint used is blue.

Let B be the amount of blue paint used in pints. Then we have:

B = 3/4 * (6.3)

Simplifying the right side:

B = 4.725

Therefore, Sue used 4.725 pints of blue paint to paint her bedroom walls.

First, we need to find the values of k and c in the linear formula G = kR + c. Let's use the highest score and the median to set up two equations:

For the highest score:
100 = k(66) + c

For the median score:
80 = k(median) + c

To find the median score, we need to first sort the raw scores in ascending order:
18, 29, 32, 35, 36, 49, 53, 64, 66
The median is the middle score, which is 36.

Substituting 66 and 36 into the equations above, we get a system of two equations with two variables:

100 = 66k + c,  
80 = 36k + c, solve for k, c

k=2 / 3
c=56
k * c =(2 / 3) * 56 =112 / 3 =37 + 1/3

1/2 I'm pretty sure there are the numbers it could land on out of 6, 3/6 = 1/2. 

18 People own a cat or a dog

You didn't put in how many student takes only Spanish but the answer should be 18 if there are 37 students that only take Spanish.

I'm going to choose NOT to respond to that...

Thank you! It was correct! 

Let's assume that there are x students taking Spanish and y students taking Chinese. Since there are 97 students in total and every student takes at least one language, we know that:

x + y = 97

We also know that there are more students in Chinese than in Spanish, so:

y > x

Now, let's consider the scenario where only x students take Spanish. In this case, all the remaining students (97 - x) must be taking Chinese. But we also know that every student takes at least one language, so:

97 - x ≥ 1 x ≤ 96

Combining these inequalities, we get:

1 ≤ x ≤ 96

Now, we need to find the number of students who take both languages. Let's call this number z. Then, we have:

z = y - x

We want to find the value of z when all the students taking Spanish are also taking Chinese. In other words, we want to find the value of z when x = z.

Substituting x = z into the first equation (x + y = 97), we get:

z + y = 97

Substituting x = z into the second equation (y > x), we get:

y > z

Now we have a system of two equations:

z + y = 97 y > z

We want to find the value of z that satisfies both equations. One way to do this is to try different values of z and see which ones work. However, we can also use algebra to solve the system.

Subtracting z from both sides of the first equation, we get:

y = 97 - z

Substituting this expression for y into the second equation (y > z), we get:

97 - z > z

Simplifying this inequality, we get:

97 > 2z

Dividing both sides by 2, we get:

48.5 > z

Since z is an integer, the only value that satisfies both inequalities is:

z = 48

Therefore, when all the students taking Spanish are also taking Chinese, there are 48 students taking both languages.

Let's consider the two cases separately:

1 - Two beads have the same color: In this case, we can choose the color for the two identical beads in 4 ways (since there are 4 colors to choose from for those beads), and we can choose the color for the remaining 4 beads in 3 ways (since we cannot choose the same color as the two identical beads). Once we have chosen the colors, there are 5 ways to arrange the beads on the bracelet (since we can rotate it). Therefore, the total number of ways to assemble the bracelet in this case is 4 x 3 x 5 = 60.

2 - Four beads have the same color: In this case, we can choose the color for the four identical beads in 4 ways, and we can choose the colors for the remaining two beads in 3 x 2 = 6 ways (since we cannot choose the same color as the four identical beads). Once we have chosen the colors, there are 3 ways to arrange the beads on the bracelet (since we can rotate it). Therefore, the total number of ways to assemble the bracelet in this case is 4 x 6 x 3 = 72.

Finally, we add the two cases to get the total number of ways: Total number of ways = 60 + 72 = 132

Therefore, there are 132 different ways Joanna can assemble her bracelet.

On Monday, 75% of the students study math, which means there are 150 math students. 15% of the students study physics, which means there are 30 physics students, and the remaining students study chemistry, which means there are 20 chemistry students.

On Monday, 20% of the physics students leave, which is 6 students, and 6 new chemistry students join, so there are now 24 physics students and 26 chemistry students.

On Tuesday, 4 physics students decide to study math instead, but they still attend the calculus lecture. Therefore, the number of math students increases by 4, and the number of physics students decreases by 4. So, after Tuesday, there are 154 math students, 20 physics students, and 26 chemistry students.

The percentage of students who do not study physics after Tuesday is (154 + 26)/200 * 100% = 90%. Therefore, 90% of the students do not study physics after Tuesday.

Maybe if you didn't cheat on your homework, you wouldn't \(\text{su} \text{ck}\) at math.

e^(1.176i) = (5 / 13)  +  (12 / 13)i

Hello, guest! Thank you for your efforts to help me ,  but unfortunately your answer is incorrect!