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1.

Let the amount invested in money market fund=M

Then, the amount invested in growth fund==2M

Then, the amount invested in income fund==3200 - 3M

0.05M + 0.10*2M + 0.07[3200 - 3M] ==250, solve for M

M==$650 - amount invested in money market fund

2 x $650 ==$1,300 - amount invested in growth fund.

$3,200 - [$650 + $1,300]==$1,250 - amount invested in income fund.

Sorry, this is my guest account. Sorry if this confuses you, but I accidentely made it when I was guest. I did not notice :(. 

cosxcosy - sinxsiny = cos(x + y) = 0.6 - 0.2 = 0.4,    x + y = arccos(0.4).

cosxcosy + sinxsiny = cos(x - y) = 0.6 + 0.2 = 0.8,   x - y = arccos(0.8).

etc.

and btw,...the vertex is    (-3,4)

Answered a few days ago, here.

web2.0calc.com/questions/arithmetic-geometric-series#r3

I do not know why electricpavlov went, but cphiII went on a little vacation. He is not on the leaderboard right now because if you do not enter web2.0calc.com for a period of time, you will be removed from the leaderboard. If you join again, you will be on the leaderboard again. 

Bump please

True

Cool ...

CPhill’s last post is almost a year old. I’m fairly sure I know why he left...

I wish the Martians took CPhill; then we could trade WAT for him.

Although, after going to the trouble of dumping WAT on this forum, I suppose they don’t want him back... 

GA

--. .- 

ok, we wouldn't want the Marians to get you.              (that is you disguised as  CPhills )

{( 0 +1i ) , ( -2 ) , ( 0 -3i ) , ( 4 ) , ( 0 +5i ) , ( -6 ) , ( 0 -7i ) , ( 8 ) , ( 0 +9i ) , ( -10 ) , ( 0 -11i ) , ( 12 ) , ( 0 +13i ) , ( -14 ) , ( 0 -15i ) , ( 16 ) , ( 0 +17i ) , ( -18 ) , ( 0 -19i ) , ( 20 ) , ( 0 +21i ) , ( -22 ) , ( 0 -23i ) , ( 24 ) , ( 0 +25i ) , ( -26 ) , ( 0 -27i ) , ( 28 ) , ( 0 +29i ) , ( -30 ) , ( 0 -31i ) , ( 32 ) , ( 0 +33i ) , ( -34 ) , ( 0 -35i ) , ( 36 ) , ( 0 +37i ) , ( -38 ) , ( 0 -39i ) , ( 40 ) , ( 0 +41i ) , ( -42 ) , ( 0 -43i ) , ( 44 ) , ( 0 +45i ) , ( -46 ) , ( 0 -47i ) , ( 48 ) , ( 0 +49i ) , ( -50 ) , ( 0 -51i ) , ( 52 ) , ( 0 +53i ) , ( -54 ) , ( 0 -55i ) , ( 56 ) , ( 0 +57i ) , ( -58 ) , ( 0 -59i ) , ( 60 ) , ( 0 +61i ) , ( -62 ) , ( 0 -63i ) , ( 64 ) } = 32 - 32i

Bro, this is the THIRD time I saw someone ask this question. Please do not ask this question again. This is making our time useless, as you never understand. The answer is no solution, and I do not want to repeat this answer. Thank you. 

As of what the first guest, i has four different stages. These stages are i, -1, -i, 1.Through these stages, we can see that i + 2i² + 3i³ + 4i⁴ is equal to 2 - 2i. As we continue to 8i⁸, the answer is 4 - 4i. We can see a pattern, which is that for each four stages, we get 2 - 2i, no matter what. 64 / 4 is 16, so therefore the answer is 16 * (2 - 2i), or 32 - 32i. 

i + [2i^2 + 3i^3 + 4i^4 + 5i^5 +..............+64i^64] ==32  -  32i

There is no solution since in the 3rd equation if we subtract p from both sides then we get r = 9, but if we get rid of the q's from the second equation we would get r to be an equal number, thus this system does not have a solution.