All Answers 358087 Answers

You use inverse sine 0.45

$$sin^{-1}0.45$$

On the web2.0 calc this is  arc sin

arc sin is the same as invers sine

[2nd] [asin] 0.45

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\mathtt{0.45}}\right)} = {\mathtt{26.743\: \!683\: \!950\: \!403^{\circ}}}$$

This graph has a horizontal asymtote at y=-1

$$109^7=429^a\\\\
log109^7=log429^a\\\\
7log109=a*log429\\\\
a=\frac{7log109}{log429}$$

$${\frac{{\mathtt{7}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{109}}\right)}{{log}_{10}\left({\mathtt{429}}\right)}} = {\mathtt{5.417\: \!746\: \!197\: \!792\: \!286}}$$

Well

5%=5/100

50%=50/100=1/2

100%=100/100=1

600%=600/100=6

5000%=5000/100=50

0%=0

so

5000%+0%=50+0=50

Thanks Chris, I keep forgetting about L'Hopital's Rule !!

Thanks anon

There is 2nd  meaning

In a degree of a polynomial is the highest power of x

eg

$$y=5x^7-3x^2+x-2$$

Has a degree of 7

lim x→ 1     [  (5 - x)^(1/2) - 2 ] / [(10 - x)^(1/2) -3 ]

Here, we have a  0/0 situation when we try to evaluate the limit. In this case, we can use something called "L'Hopital's Rule" to evaluate the limit.

Take the derivative of the numerator and the denominator.....this gives

 lim x→ 1   (-1/2)(5-x)^(-1/2) / (-1/2)(10 - x)^(-1/2) =

 lim x→ 1     (10-x)^(1/2)/(5-x)^(1/2)   now, take the limit and we get

(10-1)^(1/2) / (5 -1)^(1/2) = 9^(1/2) / 4^(1/2) =  3 / 2

If this is

(3x-1)/(3x+2)= 4         multiply both sides by 3x + 2

3x -1 = 4(3x + 2)        simplify

3x -1 = 12x + 8          subtract 12x from both sides and add 1 to both sides

-9x =  9                     divde both sides by - 9

x = -1

$$\\-4 \le x+2 <1\\
$subtract 2 through out$\\
-6 \le x <-1$$

arctan is the same as inverse tan

You use it when you have the ratio and you need to find the angle. 

I wish you would put your questions in the right way around 315.   

$$\\lim \limits_{x\rightarrow 1}\;\;\frac{\sqrt{5-x}-2}{\sqrt{10-x}-3}\\\\
=lim \limits_{x\rightarrow 1}\;\;\frac{(\sqrt{5-x}-2)(\sqrt{10-x}+3)}{(\sqrt{10-x}-3)(\sqrt{10-x}+3)}\\\\
=lim \limits_{x\rightarrow 1}\;\;\frac{(\sqrt{5-x}-2)(\sqrt{10-x}+3)}{1-x}\\\\$$

WELL THAT DIDN'T HELP AT ALL  - SO DON'T DO THAT          LOL   

I CAN'T EVEN GET THE LATEX TO DISPLAY PROPERLY 

I'VE DONE THIS ONE PROPERLY (WITHOUT L'HOPITAL'S RULE) IN A LATER POST ON THIS THREAD.  

1/3(14-5)+(-3)^2

=1/3*9+(-3*-3)

=9/3+9

=3 and 9

=12

7-4+3x0+1=7-4+0+1 = 4

First multiply both sides by 3.  That will get rid of all the fractions.

Now multiply everything in the bracket by the -1 to get rid of the bracket.

Now maybe it will be easy.  

Give it a go and add another post to this one if you get stuck or if you want me to check your answer. :)

negative 2/3

Hi Alvarez,

I just checked.

The Spanish site is displaying properly for me.

Maybe it was just a temporary problem.  

$${{\mathtt{9}}}^{{\mathtt{9}}} = {\mathtt{387\,420\,489}}$$

So your queston can be rephrased as;

Which is larger      9^99   or   9^387420849

NOW can you see which is larger?  LOL

Hello Kitty,

Lets think about what dividing by a fraction means.

$$\frac{3}{4}\div \frac{1}{4}$$

This means - how many how many    $${\frac{{\mathtt{1}}}{{\mathtt{4}}}}$$      size portions of cake can I have if I have a total of    $${\frac{{\mathtt{3}}}{{\mathtt{4}}}}$$    of a cake.

Well, there are 3 one-quarters in 3quarters of a cake so the answer is 3

---------------------------------------------------

NOW lets look at the numbers

$$\frac{3}{4}\div \frac{1}{4}\\\\
$ I have to turn the second one upside down and multiply$\\\\
=\frac{3}{4}\times \frac{4}{1}\\\\
=\frac{3}{\not{4}}\times \frac{\not{4}}{1}\\\\
=3$$

Does that help?       

Don't worry about anons rudeness he can be a bit of an a*s sometimes but we are fond of him here.  

Just ignore him.  

I can see what you mean but it is not really a bug

The calculator thinks you are asking it to change the -3 into a +3 and it does this properly.

If you want the negative just enter it as

-2e-3

I quite like to do these without algebra - I'll see if I can demonstrate my method.

the black numbers are the ones you have been given.

the ratio of boys to girls is 4:5 so in total there is some multiple of 9 students altogether.

Next you have to say

$$\begin{tabular}{|c|c|c|}\hline
boys & girls & Total\\\hline
4&5&\textcolor[rgb]{1,0,0}{4+5=9} \\\hline
& &1620\\\hline
\end{tabular}$$

$$\\\textcolor[rgb]{1,0,0}{1620\div 9 = 180} \quad $180 is the multiplication factor$\\
so\\
$number of boys is $4\times 180 = 720 \quad $Put that in the box under the 4$\\
and\\
$number of girls is $5\times 180 = 900 \quad $Put that in the box under the 5$\\\\
$Total number of $ \textcolor[rgb]{0,0,1}{ \;purple\;penguins\;} $ is $ 720+900=1620 $ that checks out very nicely. $
\\\\
$The purple penguins is an insider joke - don't worry if you don't get it - you can google it if you want, then you will know what I am talking about. $$$

8x=-6

x=-6/8

x=-0.74 or -3/4

The length of a shadow cast on level ground is proportional to the cotangent of the sun's elevation angle relative to the horizon.

Calculate the cotangent of (0.6°) then multiply by 6 feet.

Tangent (0.6) = 0.010472358322

CoTan (0.6)= (1/0.010472358322)= 95.4894751738232205

95.4894751738232205 * 6 ft. = 572.936851042939323

Length of Shadow is 573 ft.

7UP

The answer is 2. 1+1=2.

The answer is six.