Part A) From the observer’s point of view it would seem like a free fall from rest, because the ceiling, floor and person in the elevator have the same velocity. So, standard gravity acceleration would apply here.
A(Z) =-9.8m/t2* Z0 3m
Z(f) = 0
0= -0.5gt2 +Z0
T=sqr(2Z0/g)* 2*3.0m)/9.8ms2 = 0.782s
0.782 seconds to reach the floor.
Part B) 9.8ms2*0.782 = 7.67 m/s velocity at impact with floor
Part C) Observer at relative rest.* V of Z0 = +2.5m/s (initial)
A(Z) = -9.8m/s2 * Zf =V(Z0) – gt = (2.5m/s) -(9.8m/s2) (0.782s)
Zf = -5.16m/s. Velocity is (5.16m/s) for observer at relative rest.
Part D) The floor will rise ((2.5m/s)(0.782s)) =1.96m during the fall of the bolt.
The bolt appears to fall (3.00m -1.96m) =1.04m
The bolt will appear to fall 1.04m for observer at relative rest.
Relative reference frames are a little confusing. I can hardly wait until I get into the quantum s**t. I doubled checked this, but Melody, CPhill, and Alan should confirm this before you accept it.
--7UP--
