Geno's answer is correct, but let me add one proviso.
We must restrict the domain on the inverse to x ≥ - 1.
The reason for this is that if (a,b) is on the inverse graph, then (b, a ) must be on the original graph. And the minimum point on y = x^(3/2) - 1 = (0,-1). Notice that if we put -9 into y = (x + 1)^(2/3), the result is 4. So the point (-9,4) is on the inverse graph, but the point (4, -9) isn't on the original graph. And notice that if we put -1 into the inverse, it returns 0. And for all x values greaer than -1 on the inverse, the two graphs will maintain this (a,b), (b,a) relationship.
