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The rules of operation say that division and multiplication are equally important, so calculate them, in order, from left to right.

16 ÷ 4(4)              Do the division first, because it is to the left of the multiplication.

=  (16 ÷ 4)(4)

=  (4)(4)

= 16

f(x)  =  x^(3/2) - 1

y  =  x^(3/2) - 1

Step #1:  interchange x and y:

          x  =  y^(3/2) -1

Step #2:  solve for y:

          x+ 1  =  y^(3/2)

          Square both sides:  (x + 1)^2  =  y^3

          Find the cube root of both sides:  (x + 1) ^(2/3)  =  y

Answer:  y  =  (x + 1) ^(2/3) 

If you have any questions, please post back.

c-17=19 well you add 17 to both sides negative 17 and positive 17 cancel each other out so C=36

x² + 4  =  0

x²  =  -4

If you have only real numbers, there will be no solution, but if you have complex numbers:

x  =  ±√-4

x  =  ±√4·√-1       where  √4 = 2  and  √-1  can be replaced with the symbol  i

x  =  ±2i

If there are two parts to a polynomial, A and B, 

and, if you know one part, part A,

and if you know the sum of the two parts, Sum,

since  A + B  =  Sum,

the part that you don't know, B, can be found by Sum - A.

Post back a specific problem and we can help you with that.

or nah jk not jk jk jk

√32  =  √16·√2  =  4√2

4√2 + √2  =  5√2

(5√2)²  =  (5√2)·(5√2)  =  (5·5)·(√2)·(√2)  =  25·2  =  50

yall act like you never seen a white person before jaws on the floor

Will The Real Slim Shady Please Stand Up? LOLOLOL

The calculator at ths site will be able to calculate this for you.

21 :-p

To find sin(2A):

Use formula:  sin(2A) = 2sin(A)cos(A).

Draw the diagram in the third quadrant.

Since the tan(A) = 1/3, the '1' represents the y-value and the '3' represents the x-value; but, since the angle ends in the third quadrant, both the x-value and the y-value are negative.

Using the Pytagorean theorem, the hypotenuse has value √10.

Thus, sin(A) = -1/√10   and  cos(A) has value -3/√10.

sin(2A) = 2(-1/√10)(-3/√10)  = 6/10.

It calculated itself for you, my friend, but if you need a response, it is: $${\frac{{\mathtt{6\,456}}}{{\mathtt{699}}}} = {\frac{{\mathtt{2\,152}}}{{\mathtt{233}}}} = {\mathtt{9.236\: \!051\: \!502\: \!145\: \!922\: \!7}}$$

It's Morphing Time!

the answer is 19.

Denali20

math is secretly a evil torcher done in the 19th century. theye would put you on a 6 day ath course in witch you eat drink and sleep math and by the end of it you simply die on the spot. 

All are true except this one: 

"The double angle identity for sin2A = 2cos²A."

(Sin2A = 2sinAcosA)

whoa!? what happened when i was gone!?

very nice .. 

thank you melody 

cos2A = cos^2A - sin^2A

sin A = 1/√10   cosA = 3/ √10    .....so....

cos2A= (3/ √10)^2 - (1/ √10)^2 =   9/10 - 1/10  = 8/10  = 4/5

I guess you want this in percent and decimal forms........

12/15 = 4/5 = .80  = 80%

g(x) - f(x) =

(2x - 9) - (3x + 5) =

-x - 14  

tan(2A) = sin(2A) / cos(2A) =   2sinAcosA / (cos^2A - sin^A)

sinA = 1/√10  cos(A) = 3/√10   so we have

tan(2A) = 2(1/√10)(3/√10) / (9/10 - 1/10)  = (6/10) /(8/10) = 6/8 = 3/4