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or this...

I know that I am Good at maths...

-Robert

why don't ya search it up??

So, what is the answer?

And also...

If this will help.

-Robert

You're welcome

-Robert

$${\frac{{\mathtt{36}}}{{\mathtt{85}}}} = {\mathtt{0.423\: \!529\: \!411\: \!764\: \!705\: \!9}}$$Do you want that?

-Robert

PS. You are a German, though.

Ok, I have time. No worries.

Sorry, I thought there was an equal sign, not a less than sign.

It might not be the largest integer

I have an online class, and it is wrong. Sorry

If this is a democracy, I vote for CPhill's answer.

is it 11<50?

-Robert

like the square root of 36:$${\sqrt{{\mathtt{36}}}} = {\mathtt{6}}$$.

-Robert

If the problem is (x² + 10x + 21) / (x +3):

Factor the numerator:  (x + 7)(x + 3)

The problem is now:   (x + 7)(x + 3) / (x + 3)

Cancel the x + 3 factor in the numerator with the x + 3 factor in the denominator, leaving  x + 7. 

Thanks for that, Robert......

I think this is wrong, incorrect

We can prove, by induction, that  the sum of the first n positive integers squared = the sum of the cubes of the first n positive integers.

So n here, = 7

If it takes 15 laborers 40 days to dig 40 acres...then they are digging 1 acre per day. And each laborer must dig 1/15 of an acre per day.

So 20 laborers would dig 20(1/15) acres = (4/3) acres per day. So 60/(4/3) = 45 days to dig 60 acres.

Cancelling out terminating zeros in the numerator with terminating zeros in the denominator, I end with 68/20.

68/20  =  3.4

x(3x - 4)  ≤  (6x² - 3x + 5) / 10

Simplify:

3x² - 4x  ≤   (6x² - 3x + 5) / 10

30x² - 40x  ≤  6x² - 3x + 5

24x² - 37x - 5  ≤  0

Factoring:  (8x + 1)(3x - 5)  ≤  0

This divides the number line into three parts:  x < -1/8,  -1/8 < x < 5/3,  x > 5/3

Try a a number in the lower region:  I tried -1:  [8(-1) + 1][3(-1) - 5]  =  56. Since this is not less than or equal to zero, all numbers less than -1/8 will not work.

Try a number in the middle region:  I tried 0:  [8(0) + 1][3(0) - 5]  =  -5. Since this is less than zero, all numbers in this region work.    Answer:  -1/8 < x < 5/3

Try a a number in the upper region:  I tried 2:  [8(2) + 1][3(2) - 5]  =  17. Since this is not less than or equal to zero, all numbers greater than 5/3 will not work.

Now, to answer the question, you will have to figure out (count) the number of integers in the region 

-1/8 < x < 5/3.

- See more at: http://web2.0calc.com/questions/help-please_45#sthash.fDB7TCoS.dpuf

You are selecting one accountant from four, two marketing agents from three, and four board members from seven.

Since order in not important, use combinations.

4nCr1 x 3nCr2 x 7nCr4  =  4 x 3 x 35  =  420 ways