First put 1-1/3 into improper fraction...
1-1/3 = 4/3
$${\frac{{\mathtt{4}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{6}}$$
Then cross multiply... 3 will go into 6 how many times? Well, 2 • 3 = 6, so 3 will go into 6 two times...
$${\frac{{\mathtt{4}}}{{\mathtt{1}}}}{\mathtt{\,\times\,}}{\mathtt{2}}$$
Then multiply 4 • 2... which is 8...
Answer = 8
