a) The easiest way to do this one is just to cross-multiply......so we have
(2x -1)(x - 1) = (3x + 4)(x +7) expand both sides
2x^2 - 3x + 1 = 3x^2 + 25x + 28 subtract 2x^2 and 1 from both sides and add 3x to both sides
0 = x^2 + 28x + 27 factor
0 = (x + 27)(x + 1) setting both factors to 0, we have x = -1 and x = -27
Neither thing makes a denominator in the original problem = 0, so both solutions are good....
