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Just put in (numerator) / (denominator). If, for example, you type 5 / 4 x 3, that means five-fourths divided by three.

Thanks Sasini but where is the y solution?

Hi Zegroes!!

Are you and Rosala going to give us another season of “Moonlight at the Taj Mahal?”

This is way, way better than anything on TV !!!

Never mind. All is good.

Assuming that you're speaking in units of atoms, you can convert them like so:

$$Grams \Leftrightarrow Mols \Leftrightarrow Atoms$$

Using Avogadro's Constant, we know that 1 mol = 6.022 x 10^23 atoms, allowing us to convert from atoms to mols:

$$\left({\mathtt{4.87}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{22}}}{\mathtt{\,\times\,}}{\mathtt{atomsC}}\right){\mathtt{\,\times\,}}\left({\frac{\left({\mathtt{1}}{\mathtt{\,\times\,}}{\mathtt{molC}}\right)}{\left({\mathtt{6.022}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{23}}}{\mathtt{\,\times\,}}{\mathtt{atomsC}}\right)}}\right) = {\mathtt{0.808\: \!7}}{\mathtt{\,\times\,}}{\mathtt{molsC}}$$

To get grams, we convert again only from mols, to grams. Knowing that 1 molC = 12.00gC we get:

$${\mathtt{0.808\: \!7}}{\mathtt{\,\times\,}}{\mathtt{molsC}}{\mathtt{\,\times\,}}\left({\frac{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{gC}}\right)}{\left({\mathtt{1}}{\mathtt{\,\times\,}}{\mathtt{molC}}\right)}}\right) = {\mathtt{9.077}}{\mathtt{\,\times\,}}{\mathtt{gC}}$$

Good answer, SevenUp......!!!!

The area is given by

1.720477401 x s^2    where s is the side length....so we have

1.720477401 x (7)^2 =  about 84.3 square cm

Learning how to use an abacus is on my to do list. However, I do know how to use a slide rule. They make great back-scratchers.

$$\\\frac{7.3*10^3}{ 4.5*10^6}\\\\
=\frac{7.3}{4.5}\times \frac{10^3}{10^6}\\\\
=\frac{7.3}{4.5}\times \frac{10^3}{10^6}\\\\
=1.6\dot2\times \frac{10*10*10}{10*10*10*10*10*10}\\\\
=1.6\dot2\times \frac{1}{10*10*10}\\\\
=1.6\dot2\times \frac{1}{10^3}\\\\
=1.6\dot2\times 10^{-3}\\\\
OR\\\\
=\frac{7.3}{4.5}\times \frac{10^3}{10^6}\\\\
=1.6\dot2\times 10^{3-6}\\\\
=1.6\dot2\times 10^{-3}\\\\$$

The total number of ways 10 people can occupy 20 seats (in a row) is nCr(20,10) (184756).

There are only 2 ways 10 people can occupy 20 seats (in a row) that have no adjacent person.This is can be defined by odd or even seats (1,3,5 . . . or 2,4,6 . . .).

Of the 184756 combinations, only two allow for the condition specified and this gives a probability:

Derived from nCr(20,10)/2 =92378

(1/92378) = 0.0000108250882245

 _7UP_

The total cost is given by

(2/3)lbs. x $9  +  (1/4)lbs. x $7  =

$6  + $(7/4)  =

$7.75

That chicken came from a long line of other chickens.

Haha I always hear and you Tiddle now I expect to hear it every time I'm on.

Picture a right triangle with the right angle being ∠C. Label the other two angles ∠A and ∠B.

cos is defined to be the ratio of the adjacent side to the hypotenuse.

In this triangle, AB is the hypotenuse, side AC is the side adjacent to ∠A and side BC is the side opposite to ∠A.

cos∠A  =  3/5  =  AC/AB

Since this is a right triangle, use the Pythagorean Theorem to find the value of the third side:

   AC² + BC²  =  AB²     --->     3² + BC²  =  5²      --->   BC  =  4

sin is defined to be the ratio of the opposite side to the hypotenuse.

sin∠A  =  BC/AB  =  4/5

tan is defined to be the ratio of the opposite side to the adjacent side.

tan∠A  =  BC/AC  =  4/3

Right on, Tiddle.....but...where did that chicken come from???

What laid that egg, zegroes  ....?????   (this is an unresolvable issue......)

But you need a chicken first to have an egg

log₁₀N = 4  can be written as  10⁴ = N   --->   N  =  10 000

the egg this is simple the chicken cant come first cause all chickens hatch from eggs.

Let the number of away fans = x

Then, the number of home team fans is 2x - 31

So

x + ( 2x - 31) = 86

3x - 31 = 86     add 31 to both sides

3x = 117   divide by 3 on both sides

x = 39    and that's the number of away fans

And

2(39) - 31  = 78 - 31   = 47  and that's the number of home fans