So we have
√(3 +√5) - √(3 -√5)
Let √(3 +√5) - √(3 -√5) = x = √(x^2)
So we have
√ [√(3 +√5) - √(3 -√5)]^2 =
√ [3 + √5 - 2√(3 +√5)√(3 -√5)+ 3 -√5 ] =
√ [3 - 2√(9-5) + 3] =
√ [6 -2√4] =
√ [6 - 2*2] =
√(6-4) =
√2
P.S. - That was a neat little trick I learned from another member......heureka .....!!!
Thanks, heureka !!!
That's when I'm going to eat.
