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If it was an isosceles right triangle you could do it but then of course you really do know the other angles. :)

inverse cos (7/18)

or

acos(7/18)     it is the same thing.

just type in

asin(0.606)

arc sin is the same as inverse sine 

can you pls be more clear with this?

which problem are you talking about?

anonymous gave the correct answer!it is 983 becoz when you open the brackets of absolute value ....it gives the positive number only!

how about yummy pie?

lol!no!

lts try this....

$$\frac{22}{7}*\frac{22}{7}$$

now simply multiply this!

$$=\frac{484}{49}$$

now lets divide more!

$$=9.8775510204081633$$

 there we go!

Well, the answer is still 32 because "Martin WANTS to give....." WE DONT KNOW IF MARTIN EVER GAVE THE MARBLES OR NOT 

983 is the answer

I really have no idea if this is at all relevant - I suppose I should google it.     LOL

I saw the word rate so I differentiated .    

$$\frac{d}{dx}(sinx)*x^{-1}\\\\
=(sinx)*-1x^{-2}\;+\;(cosx)*x^{-1}\\\\
=\frac{-sin(x)}{x^2}\;+\;\frac{cos(x)}{x}\\\\
=\frac{xcos(x)-sin(x)}{x^2}$$

$$\frac{25}{241}<1\qquad $since the bottom is bigger than the top$\\\\
\mbox{9.34 is more than 1 so how could the two be equal??}$$

NOW

$$\frac{25}{241}\approx \frac{25}{250} = \frac{1}{10}=0.1\\\\
$0.1 is pretty close to 0.104$$$

I hope that all helps :))

Inverse tan 5.03

on this calc use              atan(5.03)

what is 1/5 % times 10

=0.2% of 10

=0.2/100 *10

=0.2/10

=0.02

Inverse trig is the same as arc trig

so use

atan, acos, and asin 

A log is an exponent (or a power or indice)

so for example

$$\\7^2=49\\\\
log_7\; 49=2$$

See how the log is the power  

No way to do this...we need to know at least one of the acute angles, as well.....

NO definitely not. 

H = 50 tan 28 = about 26.6 ft

You have presented this beautifully Nauseated but

I see NO IMPROVEMENT on Heureka's presentation.

PLUS Heureka knows how to spell LaTex properly !

Is momentum and velocity the same thing?  

(x*x*x*x)(-2)(x*x*x*x*x)(-2)³

=(-2)¹(-2)³(x*x*x*x)(x*x*x*x*x)

=(-2)⁴x⁹

=-2*-2*-2*-2*x⁹

=16x⁹

Let f(x)=-3x^2+kx+24,where k is a constant .If the y-coordinate of the vertex is 27, then k =??

Taking the derivative, we have

f'(x) = -6x + k ....and at the vertex, this = 0 so we have..

-6x + k  = 0     which implies that k = 6x at this point   .....so we have

27 = -3x^2 + (6x)x + 24  = -3x^2 + 6x^2 + 24   simplify

3 = 3x^2 

1 = x^2  →  x = ± 1

So  when x = ± 1,  then k = ±6

When x = 1, k = 6 and we have

27 = -3(1)^2 +6(1) + 24   which is true

And when x = -1, k = -6

27 =-3(-1)^2 -6(-1) + 24  which is also true

um im on a ipad soo....

You can link your url if you click the chain in the top right corner.

Edit your post and actually turn the url into a blue clickable link.

Solution

$$\small{\text{$\boxed{\vec{v}_1 = \vec{v}_2 = \dfrac {(m_1\cdot v_1 - m_2\cdot v_2 )}{ (m_1+ m_2 ) } } \quad\begin{array}{rcl}m_1 &=& 1400\ \mathrm{kg} \\v_1 &=& 12\ \frac{\mathrm{m} }{ \mathrm{s} } \end{array}\quad\begin{array}{rcl}m_2 &=& 1600\ \mathrm{kg} \\v_2 &=& 8\ \frac{\mathrm{m} }{\mathrm{s}} \end{array}$}}\\\\\\\small{\text{$\vec{v}_1 = \vec{v}_2 = \dfrac {(1400\cdot 12 - 1600\cdot 8 )}{ (1400+ 1600 ) } \ \dfrac{\mathrm{m} }{\mathrm{s}} $}}\\\\\small{\text{$\vec{v}_1 = \vec{v}_2 = \dfrac { 4000 }{ 3000 } \ \dfrac{ \mathrm{m}}{\mathrm{s}} = 1.3333\dots\ \dfrac{ \mathrm{m} }{\mathrm{s} } $}}\\\\\small{\text{$m_1\cdot \vec{v}_1 + m_2\cdot \vec{v}_2 = 1400 * 1.3333\dots \;+ \;1600 * 1.3333\dots =\; 4000\ \frac{\mathrm{kg}\cdot \mathrm{m}}{\mathrm{s}}$}}\\\end{array}$}}\\
\small ${\text{Velocity of combined cars = 1.33\overline 3(\dot 3)\; \dfrac{m}{s}\; south.}$$

Letex code stolen from Heureka _{(and vastly improved)}