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I am sorry that you are feeling so down.  Perhaps our little community can help a little.

There are a lot of nice kids that populate this place.  :)

5.099  the next number is less than five so  this is the answer.

c) infinitely many solutions     {.....the second equation is just a multiple of the first......  }

Let's look at this again

5x+6y=7   (1)

2x+3y=4   (2)

Multiply (2) by -2 and add it to the first equation.....this produces

x  = -1

And substituting this into (2) to find y, we have

2(-1) + 3y  = 4

-2 + 3y  = 4      add 2 to both sides

3y  = 6               divide by 3 on both sides

y = 2

So.....the solution is (x,y) = (-1 , 2)

6x-8y=-64   (1)

5x-8y=-60   (2)    

Subtract equation 2 from 1  ....  so we have....

x = -4               and substituting this into the first equation to find y, we have

6(-4) - 8y = - 64

-24 - 8y = -64      add 24 to both sides

-8y  = - 40   divide both sides by -8

y = -40/-8 = 5

So....the solution is (x,y) = (-4, 5)

Let "N" be the  number....then....

2N + 8 = 8      subtract 8 from both sides

2N = 0             divide both sides by 2

N = 0

Thanks MG :)

Here is the instructions for our web2 calc

Thanks Alan :)

Area = Length x Height

112.14 = Length x 8.9       divide both sides by 8.9

12.6 inches

ahh, i love my job. i get paied $5,000 a week for being awesome!!!

Thanks Alan :)

no no no, cphill, all they want to know is the fricken answer to the question, not how you got it. you just give them the answer. poor misguided cphill. just give them the fricken answer.....

2.  6^{5n + 6} = 1296    notice that 1296 = 6⁴     so.......we have

6^{5n + 6  =}  6⁴      and equating exponents, we have

5n + 6 =   4        subtract 6 from both sides

5n =   -2            divide both sides by 5

n = -2/5

7. log₂ 9  + log₂ a  = log₂ 13     and we can write

log₂ (9 * a)  = log₂ (13)      and since the logs are the same we have

9a = 13       divide both sides by 9

a = 13/9

8. log₅ (x + 2)  - log ₅ 11  = log₅ 121     and we can write

log ₅ [ (x + 2 ) / 11 ]  =  log ₅ 121      and again, since the logs are the same  we can solve

(x + 2) / 11  = 121     multiply both sides by 11

x + 2   = 1331     subtract 2 from both sides

x  =   1329

Thanks Anees220.

$$2\times y^2\times y = 2\times y\times y\times y =2y^3$$

yes you can do fractions. just use this button on your keyboard  for fractions:

/

There is a button that looks like ^y√x so use that to find the y^th root of x.

But for integer roots there is an alternative way using the x^y button beside it.

Example: There are two ways to write the 4^th root:

  ∜57 ≡ (57)^¼

So after taking the reciprocal of y you can make use of that x^y button.

Does this answer your question? 

  ♣    ♣    ♣    ♣    ♣

what grade r u in?

2)  6^{5n + 6}  =  1296   --->   6^{5n + 6}  =  6⁴   --->   5n + 6  =  4   --->   5n  =  -2   --->   n  =  -2/5

7)  log₂9 + log₂a  =   log₂13   --->   log₂9a  =  log₂13   --->   9a  =  13   --->   a  =  9/13

8)  log₅(x + 2) - log₅(11)  =  log₅(121)   --->   log₅( (x + 2)/11 )  =  log₅(121)   --->   (x + 2)/11  =  121

              --->   x + 20  =  1331   --->   x  =  1331/20

nauseated, you are a high disgrace to us. therefore, you shall be punished for your crimes.

$$\Text$ {Solution in (Non-Titanium) Roman Numerals}\\\\
\underbrace{\binom {12}{3}}_{\textrm{CCXX}} \ \cdot \; \underbrace{\binom {9}{4}}_{\textrm{CXXVI}} \ \cdot \; \underbrace{\binom {5}{5}}_{\textrm{I}} \; = \; \overline{XXV}MMDCCXX$$