Yes that is the answer!
$${\mathtt{10}}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right)}^{{\mathtt{3}}} = {\frac{{\mathtt{40}}}{{\mathtt{243}}}} = {\mathtt{0.164\: \!609\: \!053\: \!497\: \!942\: \!4}}$$
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