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 #1
avatar+173 
+5
Apr 27, 2015
Apr 26, 2015
 #1
avatar+2973 
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Apr 26, 2015
 #1
avatar+130511 
+5

 

 

I'm taking a really wild guess, here.....

I think the equations should be of this form......y = C(a/b)^x     where C = the percent of water in the wood at  x = 0  (in other words, at time  0 ) = 40% or just .40 .....if so......look at both graphs, here

https://www.desmos.com/calculator/qkd7aonn59

For the graph of  y = .40(2/3)^x,   the time required to dry the wood to 10% water content is about  3.42 hours

Fot the other graph of y = .40(3/4)^x, the time is about 4.82 hours

This makes sense......the first kiln takes the water out of the wood at a faster rate - at least, initially - than the  second one .......{we can prove this with  Calculus.......}

 

  

Apr 26, 2015
 #1
avatar+130511 
+5

I believe we have these boundaries:

0 ≤ x ≤ 8   and   0 ≤ y ≤ 4

 

And we want to know the probability that

x + y ≤ 4 , given the above bounds

 

See the graph of these regions here......https://www.desmos.com/calculator/dz5d9hoagt

 

The region bounded by the lines x =0, y = 0, x = 8  and y = 4 has an area of (8)(4)  = 32 sq units

And the region bounded by x=0, y=0 and x + y ≤ 4   has an area of (1/2)(4)(4)  = (1/2)(16)  = 8 units

 

So the probability that x + y ≤ 4, given the stated bounds = 8/32  = 1/4

 

  

Apr 26, 2015
 #1
avatar+173 
+5
Apr 26, 2015

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