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0 can go into 0 an infinite amount of times

that is a good question it is 0

Yes I love my baby cakes this much $$\infty$$ + 1

i love u melody........

antilog of x  just means 10^x

cause people want to feel better about them selfs

Thanks Alan,

Another  for me to think on.  

thanks Alan, that looks complicated :)

I am confused Rosala, you cannot delete private messages?

Can you still write messages?

Is it just effecting messages from a particular user? 

Maybe someone more technical might be able to help you?  

Thank you sevenup and 315 :)

12588.61=1.0234^x

log(12588.61)=log(1.0234^x)

log(12588.61)=xlog(1.0234)

log(12588.61)/log(1.0234) =x

(2*100*5)-50-3=953

Mmm I have to think about that one Alan :/    

I'll try to set some time aside to play with it   

I am going to assume it is a regular pentagonal prism.

a=12,      b=6     and   h=8.2

the area of the pentagon base = 5* (1/2)*6*12 = 180 thingys squared

Volume of pentagon  = 180*8.2 = 1476 thingys cubed

area of each rectangular side = 6*8.2= 49.2 thingys squared

surface area = $${\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{49.2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{180}} = {\mathtt{606}}$$   thingys squared     

Did I get the terminology correct TitaniumRome ?

Cork

True True, i suggest you do this with a firecrew nearby or at least a friend with a hose/fire extinguisher.

You can also use the function "binom(6,3)"

and the output is

$${\left({\frac{{\mathtt{6}}{!}}{{\mathtt{3}}{!}{\mathtt{\,\times\,}}({\mathtt{6}}{\mathtt{\,-\,}}{\mathtt{3}}){!}}}\right)} = {\mathtt{20}}$$

Just tell you mum to cut your fingers off now - it will be safer for all concerned :)

Oh I almost forgot. I want to use gasoline instead of water, so I can make a molotov cocktail afterward, but she also says I am to young to drink.   :)

I guess

if you want    6C3  for instance you would type

nCr(6,3)

and this is the output   :)

$${\left({\frac{{\mathtt{6}}{!}}{{\mathtt{3}}{!}{\mathtt{\,\times\,}}({\mathtt{6}}{\mathtt{\,-\,}}{\mathtt{3}}){!}}}\right)} = {\mathtt{20}}$$