All Answers 358087 Answers

"£" is just the symbol for a British Pound. Add the numbers together and then put the symbol in front of the sum. Just like adding "$".

LOL.That's a good one. Hopefully my WiFi can keep up with you suckers!

I'm using a rubbish kindle lol.

(If you didn't do it this way it should work)

Go at the bottom of the screen (forum) deep down and there should be different countries. FRA , SPA , GER etc..

With flags, click the Spanish one and you should get there directly to the front page.

In order to keep both sides of an equation equal, hence the "=", need to find a way to get c by itself, while also sustaining the proper solution. Since c^2 = c×c, you can find the square root of c^2, or in other terms, divide it by itself. But wait! You still need to keep the statment true. Find the square root of 8.53, since that was what you did to the other side of the equation.

Badinage,

Sorry I can't show the LaTeX on my device because it isn't working.

But the line does have a strong effect so you have to do the { } or it won't be long enough. Thanks for the tip.

Good...I've got the solution....let's all go over to MG1's house    !!!!

{Hey....I'll bring the pizza.....!!! }

It works fine for me.

Does the same thing for me, too   ......  I dunno'    ?????

{Ghost in the machine, perhaps  ??? }

We have

(sin^2a x sin^2a + cos^2a x cos^2a) =

sin^2a x sin^2a + (1- sin^2a) x (1- sin^2a) =

sin^2a x sin^2a + 1 - 2sin^2a + sin^2a x sin^2a  =

2 sin^4a + 1 - 2 sin^2a =

2sin^4a - 2sin^2a + 1

{Note.....other answers are possible}

Mee too! Help, please!!!

No, I havent photoshopped...

is from google...

3^x  = x ^5       take the log of both sides

log 3^x   = logx^5     and we can write

x log3  = 5 log x

Rearrange

x / log x  = 5/log 3

Mmmm....that doesn't look too promising, does it???

Let's just graph the original functions and see where they meet (if they do....!!)

Addendum......I believe I spotted Melody's error

She has

0.72X  -  16.8 =X  - 42

16.8 + 42  =  x - 0.72X

But the 16.8 should be negative

So....it should be....

-16.8 + 42  = 0.28X

25.2  = 0.28X

X = 90  = the number of 10 cent coins, originally.....

And our answers would now agree....

Hey.....no biggie......!!!!

Note......if you go to WolframAlpha and type in  "convert -17 to hexadecimal"....it will return  " -11₁₆"

In other words  -17 =  -11 in hex.......which is correct...!!!

This confirms Alan's suspicions.......

If you mean c² = 8.53 then just use the calculator to take the square root, remembering that there will be two possibilities, namely c = ±√8.53 ≈ ±2.9206

.

Figure  1

Figure  2

This image clearly shows you what happened after the peaces were rearranged.

If you want them to!  There is no reason in principle why you can't have negative hexadecimal numbers, after all they are just numbers expressed in base 16.  That said, I don't think I've ever seen them being used anywhere (negative ones, that is).

.

Thanks, Alan.....!!!

Here's my check:

This supports Chris's results.

.

I get a different answer from Melody on this one.....

Let x  be the number of 50 cent coins in the beginning

Let y be the number of 20 cent coins in the beginning

Let x + 24 be the number of 10 cent coins in the beginning

And after the spree we have

x - 18   = the number of 50 cent coins

(2/5)(x + 24) = the number of 10 cent coins = the number of 20 cent coins

So the total coins left after the spree = 2(2/5)(x + 24) + ( x -18)  = (4/5)(x + 24) + (x - 18)

And 40% of these = the number of 50 cent coins left   ....  so we have

.40[ (4/5)(x + 24) + (x - 18) ] = (x - 18)

(2/5)[ (4/5 (x + 24) + (x - 18) ] = (x - 18)

[ (4/5 (x + 24) + (x - 18) ]  = (5/2)(x - 18)   multiply through by 10

8(x + 24) + 10( x - 18) = 25(x - 18)

8x + 192 + 10x - 180  = 25 x - 450   simplify

18x + 12  = 25x - 450

462 = 7x    divide by 7 on each side

x = 66  this is the number of 50 cent coins in the beginning

And x + 24 = (66 + 24) = 90 were 10 cent coins in the beginning

And notice that (3/4)y = (2/5) (x + 24)...  so y = (8/15)(66 + 24) = (8/15)(90) = 48 coins 

So....there were 48 20 cent coins originally

Now.....let's check the math....

The total number of coins after the spree =

[(4/5)(66 + 24) + (66 - 18) ]  = 120

And (66 - 18) = 48 of these were 50 cent coins

So..... 48 / 120 = 40% were 50 cent coins

And after the spree....there were an equal number of 10 and 20 cent coins.....check ...(2/5)(90) = (3/4)(48) = 36 each

So the total spent  = (3/5)(90)(.10) + (1/4)(48)(.20) + (18)(.50)  = $16.80 

I believe Melody has a slight error

She gets 210 10 cent  coins at the start    .....and 2/5 of these are left = 84 left   

And this is equal  to the number of 20 cent coins left

And she calculates the number of 50 cent coins left = 210 - 42 =  168

So....the total coins left = [ 84 + 84 + 168]  = 336 coins left

But 168 / 336 = 50% of the coins left are 50 cent coins......and this is too much

Can anyone reconcile these differences ???

I'm not sure sorry. I don't know what else to do. :/

Yes we should let Melody Sensei awake.

And TR please no interruptions with "unnecessary things"

Wow.Just wow...

I am so sorry Rosala.

XD

you have 2 choices

#1:surrender e your soul to God

or

#2:risk dying, and forever regret

i'll leave it up to you, Coal