All Answers 358095 Answers

Np :)    

-5 divided by -4 is -9

64 = 2^6 and 25 = 5^2 so they have no common factors other than 1, which is therefore the greatest common factor.

that -3 tho.....I was actually trying..... I thought it was like a stupid trick question

 From symmetry θ = 37°/2 = 18.5°

$${\mathtt{w}} = {\mathtt{8}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{18.5}}^\circ\right)} \Rightarrow {\mathtt{w}} = {\mathtt{2.676\: \!762\: \!556\: \!016}}$$

We are not shown what other angles are needed, but the obvious ones are 90°- θ and 180°-37°

The alternative orientation is:

Here again θ = 18.5° but this time we have

$${\mathtt{L}} = {\frac{{\mathtt{8}}}{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{18.5}}^\circ\right)}}} \Rightarrow {\mathtt{L}} = {\mathtt{23.909\: \!479\: \!701\: \!948\: \!374\: \!2}}$$

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One possibility:

In that sentence, the number 0 appears _1_ times, the number 1 appears _10_, the number 2 appears _1_ times, the number 3 appears _1_ times, the number 4 appears _1_ times, the number 5 appears _1_ times, the number 6 appears _1_ times, the number 7 appears _1_ times, the number 8 appears _1_ times, and the number 9 appears _1_ times

Another possibility (?):

In that sentence, the number 0 appears _one_ times, the number 1 appears _one_, the number 2 appears _one_ times, the number 3 appears _one_ times, the number 4 appears _one_ times, the number 5 appears _one_ times, the number 6 appears _one_ times, the number 7 appears _one_ times, the number 8 appears _one_ times, and the number 9 appears _one_ times

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is it 1 time tecnically?

Start off by subtracting both sides by 3x; 2x-3+21.

Add 3 to isolate the 2x; 2x=24.

Divide by 2, and x=12.

16 ounces in 1 pound, 16 times 20 would be the number of ounces in 20 pounds.

First, let's find out the diameter by dividing the area by pi.

175.84/3.14 is 56.

The formula for the area of a circle is pi*(radius^2).

The diameter is twice the length of the radius. 56/2=28.

28 squared times 3.14 is 2461.76.

Yes, your answer is correct.

s = [7 + 8 + 9] /2  =  24/2 = 12

And using Heron's formula, we have

A = √[12 * (12-7) * (12 - 8) * (12 - 9)] =

√[12 * 5 * 4 * 3] =

√[12 * 5 * 12] =

√[144 * 5 ] =

12√5 sq units

115,000,000*.10= 11,500,000

The tangent is the ratio between the opposite side and the adjacent side of a right triangle.

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{x}}\right)} = {\frac{{\mathtt{opposite}}}{{\mathtt{adjacent}}}}$$

Since one car travels at 118 and one at 103....and the average speed is 100....we might estimate the third car's speed to  be 100 - 18 = about 82 mph

To find the exact speed:

We have

[103 + 118 + Z] / 3 = 100   multiply both sides by 3

103 + 118 + Z = 300   simpify

221 + Z  = 300 subtract 221 from each side

Z = 79 mph

We still wouldn't have at triangle because  a + c = b .....but....by the Triangle Inequality....a + c must be greater than b....

If 5x - 4y = 7  and xy = 6    find  125x^3 - 64y^3

Note   (5x - 4y)^2  = 7^2    →     25x^2 - 40xy  + 16y^2  = 49    →   25x^2  + 16y^2  = 49 + 40xy

So....factoring  125x^3 - 64y^3  ..... we have..

(5x - 4y) (25x^2 + 20xy  + 16y^2) =

(5x -4) ([25x^2 + 16y^2] + 20xy)  =

(7) ([ 49 + 40xy ]+ 20xy) =

(7)(49 + 60xy) =

(7)(49 + 60(6) ) =

(7) (49 + 360 ) =

(7)(409) =

2863 

$$\left({\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{5}}}{{\mathtt{8}}}}\right){\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{9}}}{{\mathtt{16}}}}{\mathtt{\,\small\textbf+\,}}\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right)$$

$${\frac{{\mathtt{5}}}{{\mathtt{8}}}} = {\mathtt{0.625}}$$        $${\frac{{\mathtt{9}}}{{\mathtt{16}}}} = {\mathtt{0.562\: \!5}}$$      $${\frac{{\mathtt{1}}}{{\mathtt{4}}}} = {\mathtt{0.25}}$$

Start inside the brackets:

$$\left({\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.625}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{0.562\: \!5}}{\mathtt{\,\small\textbf+\,}}\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.25}}\right)$$

$$\left({\mathtt{2.625}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{0.562\: \!5}}{\mathtt{\,\small\textbf+\,}}\left({\mathtt{3.25}}\right)$$

Then you just add the numbers:

$${\mathtt{2.625}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.562\: \!5}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3.25}} = {\mathtt{6.437\: \!5}}$$

I'm sorry;  side c = 1

7 + 6 ln x - 22.6 = 0     simplify

6 ln x - 15.6  =  0          add 15.6 to both sides

6 ln x = 15.6     divide both sides by 6

ln x = 15.6 / 6

So

x =  e^(15.6 / 6)  = about 13.46