All Answers 358115 Answers

Area of ABC =  (1/2)(BC)(AD) =

(1/2)(3.5 )(3.5)  ≈ 6.125 sq cm

Here's a pic.......

If the width is x, then the length is 2x.

The perimeter will be two widths plus two lengths:  2(x) + 2(2x)  =  2x + 4x  =  6x

Since the perimeter is 54:  6x  =  54   --->   x = 9 meters (width)  and  2x = 18 meters (length).

The area is length times width:  9 m  x  18 m  =  162 m².

The sum of supplementary angles is 180°.

A set of data may have no mode by having the same number of each data value; in that case just say "no mode".

The circumference and the perimeter are basically the same thing.

Area of a triangle ABC = area ABD - area ACD

Area ABC = 8.75cm² - 2.6cm²

Area ABC = ≈6.15cm²

hey rosie!

1/3*pi*2^2*sqrt(10^2-2^2) =

(1/3) * pi * 4 * √[100 - 4 ] =

(1/3) * pi * 4 * √[96] = 

(1/3) * pi * 4 * 4 √6 =

(16/3) * pi *  √6  =

about  ....   41.042

Almost correct.....!!!

5(-4 - 8d) - 6d =

-20 - 40d - 6d =

-20 - 46d

good good I was getting tired of the P**n and the cussing and fighting

We can also solve this  with an equation.

Let x be the number of months that Jennifer has been collcting stamps and  (x -3) the number of months that Allison has been colllecting stamps.

So......

4x = 6(x-3)

4x = 6x - 18    add 18 to both sides   and subtract 4x from both sides

2x = 18            divide both sides by 2

x = 9

And 9 months after January is September........as Anonymous has said.....

wow, thank you so much Alan, you just saved me.

We are well, same always: trying to keep out spammers!!!!!

Probability that A wins on first throw = 1/6

Probability that A and B lose their first throws and A wins on his 2nd throw = (5/6)²1/6

Probability that A and B lose their first two throws and A wins on his 3rd throw = (5/6)⁴1/6

etc.

So probability that A wins = (1/6)(1 + (5/6)² + (5/6)⁴ + ...)

This is a geometric progression with sum = (1/6)/(1 - (5/6)²) = 6/11

So the probability that A wins = 6/11

.

(3p - 1)(p + 5)

Notice that -1*5 = 5 and 3*5 - 1*1 = 14

.

January Jennifer begin Collecting 4 postage stamps per month in April her friend Allison started collecting six stamps per month what month will Jennifer and Alison have a number of stamps

January February March April May June July August September October November December

Jennifer                  4            8          12     16    20   24   28     32         36             40         44            48

Allison                                                       6     12   18   24     30         36    

Answer- September

11b+7=40

11b = 40-7

11b = 33

b = 33/11

b = 3

We'd need to know something about its dimensions.......!!!!

Im happy that you are happy here...

All this people is are amazing...

The side of the rhombus = 68 / 4 = 17

And the diagonals meet at right angles. So....one side and (1/2) of the length of any diagonal form two sides of a right triangle, with the side forming the hypotenuse and the half-diagonal forming a leg.

So the remaining leg is formed by the other (1/2) diagonal and is given by √[17^2 - 15^2]  = √[289 - 225] = √64 = 8.  So the other diagonal = 16.

And....the total area will be given by   (1/2)ab    where a is the length of one diagonal and b is the length of the other......so we have....

(1/2)(30)(16)  = 240 sq. units

how do i find the altitude of the hypotenuse?

.......................................................................

You probably want to know how to calculate  height BH (see image).

 To calculate the height (BH) you need one side and an angle .

Exemple(1):   BC = 4      (gamma) ɣ = 36.9^o

                 sin(ɣ) = BH/BC

                 BH = 4 * sin36.9^o

                 BH = 2.4

Exemple(2):   AC = 5       (alpha) α = 53.1^o

       In this case, you need to find the side AB first than to calculate the height.

                 AB = 5 * cos53.1^o

                 AB = 3

                 BH = AB * sin(α)

                 BH = 3 * sin53.1^o

                 BH = 2.4

BD = 3.5/tan(35°)

CD = 3.5*tan(23°)

Area of triangle ABC = 1/2(3.5²/tan(35°) - 3.5²*tan(23°))

$${\mathtt{Area}} = \left({\frac{{{\mathtt{3.5}}}^{{\mathtt{2}}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{1}}}{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{35}}^\circ\right)}}}{\mathtt{\,-\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{23}}^\circ\right)}\right) \Rightarrow {\mathtt{Area}} = {\mathtt{6.147\: \!498\: \!292\: \!005\: \!575\: \!7}}$$

Area ≈ 6.147cm².