$$\\f(x)=(x^2-4)-1\\
f(x)=x^2-5\\
f(1)=1^2-5\\
f(1)=1-5\\
f(1)=-4\\
if\;v=1\;then\;w=-4$$

GIVEN: √x=-2 ; what are the solutions for x? (HINT: you can graph it!!!)

What is 98(0.05) to the 14th power?

IT IS THE 20th root of 98 in parenthesis to the 14th power.

I do it from scratch each time

$$\\180\;degrees=\pi radians\\
so\\
1\;degree=\frac{\pi}{180\;}radians\\
so\\
x\;degrees=\frac{\pi}{180\;}\times x \;\;\;radians\\$$

(2yx4y)+(4y-3y)=

(4y-3y) is 1y or y

[2*4 = 8; y^2; x] + y

therefore (8xy^2 + y)

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{48}}^\circ\right)}{\mathtt{\,\times\,}}{\mathtt{13}} = {\mathtt{8.698\: \!697\: \!882\: \!667}}$$

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{48}}{\mathtt{\,\times\,}}{\mathtt{13}}\right)} = -{\mathtt{0.104\: \!528\: \!463\: \!268}}$$

GIVEN: Right Angle Triangle has the following characteristics - 90 degree angle & 2 sets of 45 degree composites (partners); therefore 90 + 45 + 45 = 180 degrees (THEOREM)

ie) sin (0) = height/hypotenuse;

let height = y-axis

let hypotenuse = z-axis (diagonal)

ie) sin (0) = y/z; therefore y(height) = z * (sin(0)), .. I think

THEN... sin (45 degrees) = blah blah blah

I am surprised that there are no imaginary solutions for this.  

WolframAlpha sys that there are none.

No!

...............

What other information are you given?

If you have the length of the other two sides then you can use Pythagoras's theorem.

If you have an angle and one of the other sides then you can use a trigonometric function.

.

In sport, win rate is defined as number of wins divided by number of games played, and is usually expressed as a percentage, so here we have win rate = (5/7)*100 ≈ 71.4%

.

Thanks DarkBlaze347

I like that you have not just given the answer :)

It is best when askers are expected to a little for themselves.   

GIVEN: 7 games won (positive/negative) vs. 2 games lost = winning rate calculated with

     parameters/policies/regulations designated by sport event with its leaders, an

     association and licensed institution.

ANSWER = undefined OR N/A (not applicable)

It is from 100% to 200%, otherwise it's undefined.

Area = pi*(diameter/2)^2

You can plug in the numbers.

I am not at all sure what youare talking about but there is a graph that might be relevant  

invers sin of negativ number ?

$$\boxed{\mathbf{
\arcsin{(-x)} = {-\arcsin (x)}
}}$$

Given: Surface Area of Rectangular Prism, such that a rectangular prism exists & IS SO NO TO BE CONFUSED WITH A TRIANGULAR PRISM.

i) Since the Volume of a Rectangular Prism = r^3, the Surface Area of a Rectangular Prism is the anti-derative I believe, or to say it in layman's terms, the Integral of 1/4r^4.

ii) Therefore, the Surface Area of a Rectangular Prism = 1/4r^4

ok.

7 days is how many hours ?

$$\small{\text{$
\begin{array}{rcl}
7~ \rm{days}
\cdot \left( \dfrac{ 24 ~\rm{hours} } { 1~\rm{day} } \right)
&=& 7\cdot 24 ~\rm{hours} = 168 ~\rm{hours}
\end{array}
$}}$$

The volume of a water tank with radius 10m is 4000m3. Calculate the height of the tank to the nearest metre

$$\boxed{\mathbf{
V_{\rm{Tank}}=(\pi \cdot r^2)\cdot h
}
}
\small{\text{$
\qquad r = 10 ~\rm{m} \qquad V_{\rm{Tank}}=4000 ~\rm{m^3}
\qquad \rm{height}_{\rm{of~the~tank}} = h = ~?
$}} \\\\\\
\begin{array}{rcl}
h &=& \dfrac{ V_{\rm{Tank}} } {\pi \cdot r^2}\\\\
h &=& \dfrac{ 4000 ~\rm{m^3} } {\pi \cdot (10 ~\rm{m})^2}\\\\
h &=& \dfrac{ 4000 ~\rm{m^3} } {\pi \cdot 100 ~\rm{m}^2}\\\\
h &=& \dfrac{ 40\not{0}\not{0} ~\rm{m^3} } {\pi \cdot 1\not{0}\not{0} ~\rm{m}^2}\\\\
h &=& \dfrac{ 40 ~\rm{m^3} } {\pi ~\rm{m}^2}\\\\
h &=& \dfrac{ 40 } {\pi} ~\rm{m}\\\\
h &=& 12.7323954474 ~\rm{m}\\\\
h &\approx& 13 ~\rm{m}
\end{array}$$

I am not technical at all I am sorry.

I was using Firefox but I had problems with it (different from yours) and I returned to Google Chrome.  :/

Thanks for answering that MathsGod1

Well I will give you 100% for your initiative but that site made it look really hard.

It is not hard!

14.5% = 14.5/100 or  0.145

of   means multiply

so

14.5% of 215

= 14.5/100    x     215            See it is really simple.

$${\frac{{\mathtt{14.5}}}{{\mathtt{100}}}}{\mathtt{\,\times\,}}{\mathtt{215}} = {\frac{{\mathtt{1\,247}}}{{\mathtt{40}}}} = {\mathtt{31.175}}$$

225/324 = 25/36

(The highest common factor is 9)

-2/(1 1/2) = -2/(3/2) = (-2/1)*(2/3) = -4/3 = -1 1/3

Anything to a negative power is the same as 1 over that number to a positive power: 

$${{\mathtt{a}}}^{-{\mathtt{1}}} = {\frac{{\mathtt{1}}}{{{\mathtt{a}}}^{{\mathtt{1}}}}}$$

So for (1/4)^-1 . . . 

$$\frac{1}{(\frac{1}{4})^1} = \frac{1}{1}\times(\frac{4}{1})^1 = 4$$

Note that when you divide by a fraction you instead flip the denominator and numerator. When you get more practiced at this you can go straight from (1/4)^-1 to 4, as long as you know the process behind it.

In the same way . . .

$$\frac{1}{(\frac{1}{4})^2} = \frac{1}{1}\times(\frac{4}{1})^2 = \frac{4^2}{1^2} = 4^2 = 16$$

$$(\frac{1}{4})^2 = \frac{1^2}{4^2} = \frac{1}{16}$$