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is that a division sign?i dont think so!

duh! Walmart! Everythings at walmart!

where do you buy it?do they carry a first aid box or what?

I think your equation solution is correct but you havwe done it the very long way :)

Before you think about what to get rid of you have to think about whether either side can be simplified.

So it is

Can i simplify the sides independently?   If so do it.

What do I want to get rid of?  How? Do it - to both sides.

Can i simplify the sides independently?   If so do it.

What do I want to get rid of?  How? Do it - to both sides.

Can i simplify the sides independently?   If so do it.

etc  etc

This is why I wanted to see if you can simplify terms properly :)

$$\begin{array}{rrlll}\\\\
2(x-3)+5x&=&4(x+2)-5\qquad&(2x-3)=2x-6\;and\;4(x+2)=4x+8\\\\
2x-6+5x&=&4x+8-5\textcolor[rgb]{0,0,1}{\;\;excellent\; start!\;}\qquad&(+5\;on\;both\;sides)\\\\
&&&\textcolor[rgb]{0,0,1}{\mbox{but now, before you start adding and subtracting things you need to simpliey each side seperately}}\\\\
2x+5x-6&=&4x+8-5\\\\
7x-6&=&4x+3&Now\; add\; 6 \;to \;both \;sides\\\\
7x-6+6&=&4x+3+6&Now\; simplify\\\\
7x&=&4x+9&Now\; subtract\;4x\;from\;each\;side\;\\\\
7x-4x&=&4x-4x+9&Now\; simplify\;\\\\
3x&=&9&Now\; divide\; both \;sides\; by\; 3\;\\\\
\frac{3x}{3}&=&\frac{9}{3}&Now\; simplify\;\\\\
x&=&3&\;\;\\
\end{array}$$

I patch them up with a godzilla bandaid

but what if they start bleeding -_-

*sigh* This is why I stick to godzillas ;)

only left with thorns right now......

hmm. Im worried about you rosala. Seems like you've lost a few petals recently.

idk.......

Why has it flopped? And what would the game of contained?

yes i do.....but i am very sad....i thought of a game and it feels the idea has just flopped....a starting day full of stars and an ending day full of hot sun rays...isnt it saddening!

but, I thought one of the things you liked about me was me not being serious :P.

no no no...im the leader...if you be then well have GODZILLAS visitng every minute in our meeting house....

and Zegroes pls be serious .....i dont wanna spoil my game...i wonder if that tin is stil asleep!

was that for makign you diet?

I dont know rosala I think i should be the leader :P

^ Illuminati confirmed? lol I dont know what that problems about melody?

ok lets look at this

Q2) 5x*6yx=30xy     Nope 

Q3) 3(x+4)=12x    -      (3*x)+(3*4)=12x        nope 

Q4) -2(x+4)=-10x         -       (-2*x)+(-2*4)=-10x      nope

Q5) 17 - 4x -x +5=22+(-5x) (good)=22-5x     

 (like terms -x & -4x and 17 & +5) 17+5=22   /    -4x-x=-5       -4x-x=-5x   

Q6)3-4(5x-6)=23x+24           -  (Not sure but...)   (-4*5x)+(-4*-6)=-20x+24 good +    (3*5x)+(3*-6)=15x+(-18x)   15x+(-18x)-20x+24=-23x+24    now you have lost it  

Q7) 3x/2 + 4x/5 = 12x+10   No

Q8) 0.06*0.3=0.018        (6*3=18/1000=0.018 )  good

Q9) 0.06/0.2                  (6/2=3/1000=0.003)   please try to spot your own error 

Q10) 3x^2 +2x +5= 3x^2+2x+5       (Like terms none) the answer is given    great

Q11) 5x+2/6y * 9xy^2= ....Have no idea.   fair enough  

WAIT.  9xy^2 as a fraction...ah    

Can you fix any of your own errors MG ?

aw this post made me throw up more rainbows then a bag of skittles..... Funny I was eating a sandwitch when i thought, hmm. This could use more cheese! Then i saw your post rosala and i didnt need anymore so, thanks

ok i will surely do!

and for a correction you should say i made a late response not a long response......ok!

8*0.6*-3+4+7.67   =   {remember.....we perform multiplication/division from left to right before addition/subtraction  }

[8 * 0.6] * (-3) + 4 + 7.67  =

[4.8 * -3 ]  + 4  + 7.67  =

-14.4  + 4 + 7.67  =

-10.4 + 7.67  =

-2.73

Silver Rager! Cool!

Also, sorry for the long response, i was doing Latex in that time (lol), it takes a lot of time to do, but the results are very satisfying.

Also, when you were gone i created a new post called Latex -part 2

Just hit the"2nd" button......you will see "atan"    ......this is the tangent inverse.....

It is just [2nd] [atan] 

arctan is the same as inverse tan :)

$$\begin{array}{rrlll}\\\\
2(x-3)+5x&=&4(x+2)-5\qquad&(2x-3)=2x-6\;and\;4(x+2)=4x+8\\\\
2x-6+5x&=&4x+8-5\qquad&(+5\;on\;both\;sides)\\\\
2x-1+5x&=&4x+8\qquad&(+1\;on\;each\;side)\\\\
2x+5x&=&4x+9\qquad&(-2x\;on\;each\;side)\\\\
5x&=&2x+9\qquad&(-2x\;on\;each\;side)\\\\
3x&=&9\qquad&(Divide\;both\;side\;by\;3)\\\\
\frac{3x}{3}&=&\frac{9}{3}\qquad&(Cancel\;out)\\\\
3&=&x\\\\
x&=&3
\end{array}$$

This is my answer and i swear I haven't looked at Zacs post yet, i care about my education and if i don't make mistakes then i'll make progress, if i get it wrong and don't cheat it's better than cheating and getting it right.

I think i got it wrong at the first step, but then I got a result.

Took me about 15-20min to do. 

Code:

\begin{array}{rrlll}\\\\
2(x-3)+5x&=&4(x+2)-5\qquad&(2x-3)=2x-6\;and\;4(x+2)=4x+8\\\\
2x-6+5x&=&4x+8-5\qquad&(+5\;on\;both\;sides)\\\\
2x-1+5x&=&4x+8\qquad&(+1\;on\;each\;side)\\\\
2x+5x&=&4x+9\qquad&(-2x\;on\;each\;side)\\\\
5x&=&2x+9\qquad&(-2x\;on\;each\;side)\\\\
3x&=&9\qquad&(Divide\;both\;side\;by\;3)\\\\
\frac{3x}{3}&=&\frac{9}{3}\qquad&(Cancel\;out)\\\\
3&=&x\\\\
x&=&3
\end{array}