A list of 10 positive integers, each less than 15, has an average of 6.
What is the maximum number of ones (the number 1, not the digit) that could be in the list?
Since the average of 10 numbers is 6, that means the total of those numbers is 60.
If you have nine 1's, can you get the other 51 with one number. No.
If you have eight 1's, can you get the other 52 with two numbers. No.
If you have seven 1's, can you get the other 53 with three numbers. No . . . three 14's is only 42.
If you have six 1's, can you get the other 54 with four numbers. Yes . . . three 14's and one 12..
So the most 1's you can have is 6 of them.
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