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@above i tried to make it comfusing

this is eays to solve!

7/6 - 2/3

now first we will take the common denominator!

=7x3/6x3  -  2x6/3x6

= 21/18 - 12/18

now simply subtract!

= 9/18 

now dividing further we get

= 1/2

voila.....wasnt that a piece of cake!??

sorry i didnt read the question properly......anyway....the asnwers same!

7 by mathematics...btw how will i delete them?i just know how to throw them!

Hello CPhill

Depends on how much  You can take 60 seconds on writing this while 70 painters paint a small fence 3*3 fence

Which can we do faster.......paint that fence or answer this question?????

{ I say its a toss up..... }

ok we might as well all answer this question!

This is how I was trained to do it

$$\\T\alpha \frac{L}{N} \\\\
T=k* \frac{L}{N}\qquad but\\\\
5=k* \frac{200}{3}\qquad so\\\\
k=\frac{3}{40}\qquad so\\\\
T=\frac{3L}{40N}\\\\
$When N=5 and L=500$\\\\
T=\frac{3*500}{40*5}\\\\
T=7.5 \;\;hours$$

If 3 painters paint 200 ft of fence in 5 hours, in 1 hour, they must paint 40 ft.......so each painter paints 40/3 ft per hour.

Then, 5 painters can paint 200/3 ft every hr........so........500/ (200/3)  = 1500/200  = 7.5 hrs.

$$\\\left(x-\frac{2}{(x+1)}\right)\div \left(1-\frac{4x+7}{x^2+4x+3} \right) \\\\
=\left(\frac{x(x+1)-2}{(x+1)}\right)\div \left(\frac{x^2+4x+3-(4x+7)}{x^2+4x+3} \right) \\\\
=\left(\frac{x^2+x-2}{(x+1)}\right)\div \left(\frac{x^2-4}{x^2+4x+3} \right) \\\\
=\frac{x^2+x-2}{(x+1)}\times \frac{x^2+4x+3} {x^2-4}\\\\
=\frac{(x+2)(x-1)}{(x+1)}\times \frac{(x+3)(x+1)} {(x-2)(x+2)} \\\\
=\frac{(x-1)}{1}\times \frac{(x+3)} {(x-2)} \\\\
=\frac{(x+1)(x+3)} {(x-2)} \\\\
=\frac{x^x+4x+3} {x-2} \\\\$$

If I haven't made any stupid mistakes then that will be ok :)

You need to check it!

Cool!!!!

Yeah, I saw it...

If you read the first part, I promoted a hashtack (( on this forum )) titled 

#enjoythemusic

Dont worry about, it is just a dumb...

What music Dbg ?   You did not post any music clips    

Did you look at my clip?

cscx = 1/sinx

secx = 1/cosx

so left-hand side = 1/(sinx*cosx)

cotx = 1/tanx

so right-hand side = 1

Therefore the statement cscx*secx = cotx*tanx is false.

.

The rate at which fence painting is done is 200/(3*5) feet per painter-hour.

In order to paint 500 feet we need 500*3*5/200 painter-hours

With 5 painters the time taken is 500*3*5/(200*5) hours = 7.5 hours

.

It is 1- the probability that they all have different birthdays

$$\\=1 - (\frac{365}{365}*\frac{364}{365}*\frac{363}{365}*\frac{362}{365}*\frac{361}{365}*......*\frac{366-25}{365})\\\\
=1- (\frac{365}{365}*\frac{364}{365}*\frac{363}{365}*\frac{362}{365}*\frac{361}{365}*......*\frac{365-24}{365})\\\\
=1- (\frac{365P24}{365^{25}})$$

$${\mathtt{1}}{\mathtt{\,-\,}}{\frac{{\left({\frac{{\mathtt{365}}{!}}{({\mathtt{365}}{\mathtt{\,-\,}}{\mathtt{25}}){!}}}\right)}}{{{\mathtt{365}}}^{{\mathtt{25}}}}} = {\mathtt{0.568\: \!699\: \!703\: \!969\: \!463\: \!9}}$$

So P(2 or more have the same birthday) is  approx 0.57      or    57% 

The probability that none have the same birthday is (364/365)*(363/365)*(362/365)*...*(341/365) ≈ 0.431

So the probability that at least 2 have the same birthday is 1 - 0.431 = 0.569

.

how to represent -77,626 in binary form ?

$$\begin{array}{rcrr}
& & \rm{q o u t i e n t} & \rm{r e m a i n d e r} \\
77626& : 2 = & 38813 & 0 \\
38813 & : 2 = & 19406 & 1 \\
19406 & : 2 = & 9703& 0 \\
9703 & : 2 = & 4851& 1 \\
4851 & : 2 = & 2425& 1 \\
2425 & : 2 = & 1212 & 1 \\
1212 & : 2 = & 606 & 0 \\
606 & : 2 = & 303 & 0 \\
303 & : 2 = & 151 & 1 \\
151 & : 2 = & 75 & 1 \\
75 & : 2 = & 37 & 1 \\
37 & : 2 = & 18 & 1 \\
18 & : 2 = & 9 & 0 \\
9 & : 2 = & 4 & 1 \\
4 & : 2 = & 2 & 0 \\
2 & : 2 = & 1 & 0 \\
1 & : 2 = & 0 & \textcolor[rgb]{1,0,0}{1} \\
\end{array}$$

$$\begin{array}{rcl}
77626_2~&=& \textcolor[rgb]{0,0,1}{0}~\textcolor[rgb]{1,0,0}{1}~0~0~1~0~1~1~1~1~0~0~1~1~1~0~1~0\\
\mathbf{Invert~all~places} &=& \textcolor[rgb]{0,0,1}{1}~\textcolor[rgb]{1,0,0}{0}~1~1~0~1~0~0~0~0~1~1~0~0~0~1~0~1\\
\mathbf{+1} &=+ & \textcolor[rgb]{0,0,1}{0}~0~0~0~0~0~0~0~0~0~0~0~0~0~0~0~0~1\\
-77626_2~&=& \textcolor[rgb]{0,0,1}{1}~0~1~1~0~1~0~0~0~0~1~1~0~0~ 0~1~1~0
\end{array} \\\\
\textcolor[rgb]{0,0,1}{\mathrm{sign: \qquad 0 = + \qquad 1 = -}}$$

And #enjoythemusic????

$$\\\frac{-1}{8}\times\frac{-4}{5}=\frac{-1*-4}{8*5}=\frac{+4}{+40}=\frac{2}{20}=\frac{1}{10}$$

There you go - any questions ?

Here was your question from your last thread that you have not answered yet :)

Can you simplify this one for me ?  Do it with cancelling.  

Can you remember how to do that or do you want me to show you?

$$\frac{21x}{y}\times \frac{8y^2x}{14t}$$

Express  as a common fraction.

$$\left\begin{array}{rcl}
10 \times 3.\overline{7} &=& 37.\overline{7} \\
1 \times 3.\overline{7} &=& 3.\overline{7} \\
\hline
\end{array} \right\} -$$

$$\begin{array}{rcl}
(10-1)\times 3.\overline{7} &=& 37.\overline{7} - 3.\overline{7} \\
9 \times 3.\overline{7} &=& 34 \\
9 \times 3.\overline{7} &=& 34 \qquad | \qquad : 9 \\
3.\overline{7} &=& \dfrac{34}{9}
\end{array}$$

So far I know:

• Fractions
• Squaring
• Square root
• New Lines
• Colours
• Bigger (lines etc...)
• Array

Maybe other small things, but I've covered the basics...I think?