All Answers 358150 Answers

17.33 times 0.15= 2.5995

1.7777777777778e+31

You can use a system of equations to solve this problem.

Let s be small drinks, and l be large drinks.

3s+5l=3125

s+l=735

You can use substitution, elimination, or graphing to solve.

Elimination:

3s+5l=3125

To make the l coefficients the same, multiply the bottom equation by 5:

3s+5l=3125

5s+5l=3675

Subtract: -2s=-550.

275 small drinks were sold.

Substitution:

3s+5l=3125

s+l=735.

Isolate l on one of the equations: l= 735-s.

Substitute: 3s+(3675-5s.)=3125.

-2s+3675=3125.

-2s=-550

s=275.

4x-3y = 10

4x+1y=18        Let's just subtract these equations from each other.....this results in the folllowing....

  [4x - 3y = 10]                4x - 3y = 10  

-[4x + 1y = 18]              -4x - 1y = -18

                                      ----------------  

                                            - 4y  = - 8

And dividing both sides by -4, we have that y = 2

And substituting this back into either of the original equations, we can find x...so.....

4x + 1(2)  = 18

4x  +  2  =  18        subtract 2 from each side

4x  = 16       divide by 4 on each side

x = 4

So the solution is :    x= 4  and y = 2

Subtract x from both sides: x+8=-9.

Subtract 8 from both sides: x=-17.

Angle C must  = [180 - 73 - 57 ] = [180 - 130] = 50°

And using rhw Law if Sines, we have.....

AB/sin C  = AC/sin B    →   24/sin(50) = AC/sin(73)   →    AC = 24*sin(73)/sin(50)  = about 29.96 in

-1+10=9         

Use the fact that sin(30) = height/200

$${\mathtt{height}} = {\mathtt{200}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{30}}^\circ\right)} \Rightarrow {\mathtt{height}} = {\mathtt{100}}$$

height = 100 m

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If you mean ^, it's called a caret and is obtained (on my keyboard at least) by shift_6

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First rewrite 2x + 3y = 12 as  y = -(2/3)x + 4.  The slope of this line is -(2/3), so the slope of a line perpendicular to this must be +(3/2).  

This means the equation of the perpendicular line is of the form y = (3/2)x + k  where k is a constant.

We can find the value of k because we know the line must pass through the point (-5,1).  That is:

1 = (3/2)*(-5) + k

k = 1 + 15/2

k = 17/2

Hence the line passing through (-5, 1) is y = (3/2)x + 17/2

or, by multiplying through by 2, we could rewrite this as 2y = 3x + 17

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A circle has a diameter of 12 inches. It is placed in a square whose sides have a length of 12 inches. What is the percent of the area of the square that is covered by the circle?

Area of the square is: 12² = 144 in²

Area of a circle is:  6² *pi = 113.1 in²

144in² /100 = 113.1in² /x

x = 78.54%

$$\begin{array}{rrlll}\\\\
2x+8&=&x-9\qquad&(-x\;on\;each\;side)\\\\
2x+8(-x)&=&x-9(-x)\\\\
x+8&=&-9\qquad&(-8\;on\;each\;side)\\\\
x+8(-8)&=&-9(-8)\\\\
x&=&-17
\end{array}$$

Sorry! 

$$\frac{2^{30}}{8^9}\rightarrow\frac{2^{30}}{(2^3)^9}\rightarrow\frac{2^{30}}{2^{27}}\rightarrow2^{30-27}\rightarrow2^3$$

so x = 3

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-1+10 = 9

If it was 0+10=10

But as it has gone one below zero (a negative) it's 9.

-1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 

$$(1-\tan x)\sec{2x} \rightarrow \frac{1-\tan x}{\cos{2x}} \rightarrow \frac{1-\tan x}{\cos^2{x}-\sin^2{x}}\rightarrow \frac{1-\tan x}{(1-\tan^2{x})\cos^2{x}}\\\\\rightarrow \frac{1-\tan x}{(1-\tan{x})(1+\tan{x})\cos^2{x}}\rightarrow \frac{1}{(1+\tan{x})\cos^2{x}}$$

tan(pi/4) = 1  and cos(pi/4) = 1/√2 so:

$$\frac{1}{(1+\tan{\frac{\pi}{4}})\cos^2{\frac{\pi}{4}}}=\frac{1}{2\times \frac{1}{2}}=1$$

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First you need to add the two values in the parethesis together. Next take that value and raise it to the 60th power. Finaly muliplty that value by 150,000. Remember order of operations. 

http://www.google.com/imgres?imgurl=http://www.webquest.hawaii.edu/kahihi/mathdictionary/images/PEMDAS.png&imgrefurl=http://www.webquest.hawaii.edu/kahihi/mathdictionary/O/orderofoperations.php&h=616&w=590&tbnid=Upeb2Usklw4UZM:&zoom=1&tbnh=160&tbnw=153&usg=__F9xOxc_V7Vhr9Kw5vj2yq9XoTbw=&docid=l6XKKPl9hB4h7M&itg=1

This factors as (3*cos(x) - 1)(cos(x) - 2) = 0

Since -1 ≤ cos(x) ≤ 1 the only valid solution is cos(x) = 1/3 so:

$${\mathtt{x}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right)} \Rightarrow {\mathtt{x}} = {\mathtt{70.528\: \!779\: \!365\: \!509^{\circ}}}$$

This is a first quadrant solution. There is another solution in the fourth quadrant obtained by subtracting the above from 360°.

Homework is something to do if you're not going fishing.

It depends on the shape of the house.