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Lets assume the die are rolled one at a time (it makes no difference)

The number of ways you can get 1,1, not 1 is 5

The not 1 can be 1st 2nd or 3rd.     That is 3 different ways so that makes   5*3=15

then you could have 1,1,1,                                 so that makes 15+1=16

This would be the same for all the other pair combinations and there are 6 numbers on a die so

16*6 =  96 possibilities.     

That is what i think :)

$$0.3=\frac{3}{10}$$

a shopkeeper bought 1257 tins of paint Each tin had 7 e of paint if he sold 620 tins how much paint had he left

(1257-620)* 7  e           (Was e meant to be litre?)

6 = (x+5)/(x-5)  Multiply both sides by x-5 

6(x-5) = x+5    Multiply the terms in brackets on the left-hand side by 6

6x - 30 = x + 5  Subtract x from both sides

5x - 30 = 5     Add 30 to both sides

5x = 35          Divide both sides by 5

x = 7

You can use the calculator on the home page here to answer this.  Enter:  factor(54) and press the = sign to get 2*3³.

Use the fact that the tangent of this angle will be given by the y-velocity divided by the x-velocity.

tan(38°) = 34/v_x

v_x = 34/tan(38°) = 43.52 m/s

what is the fraction form of 0.27

Multiply by 100/100=(.27 x100)/100=27/100,

So your answer is 27/100

example of two whole number factors with a product of 9 please answer

How about 3 X 3=9

The sqrt of 76,843=277.2057 approx.

how did i get 18 for 6/7 times 21,

Just multiply 21 X 6/7=(21 X 6) / 7 =126/7=18

3x^6)^4,

Your answer is 81x^24

A supplement of an angle is 6 times as large as a compliment of the angle. Find the measure of the angle, it's supplement, and it's compliment. No explanations needed.

The angle should be 72 degrees, so that,

Its compliment=90 - 72=18, and

Its supplement=180 - 72=108 degrees, which is 6 times the compliment angle of 18 degrees.

Cosec(y)=1/sin(y)

so to divide by sin(y) is the same as multiplying by cosec(y)

just like       $$\\3\div \frac{1}{2}=3\times \frac{2}{1}=3\times2$$

A grid with 3 rows and 52 columms is tiled with 78 identical 2x1 dominoes. How many ways can this be done such that exactly two of the dominoes are vertical?

Details and assumptions

the dominies will cover the entire board. They are not allowed to jut over the board, or overlap with each other.

Rotations and reflectionscount as distinct ways.

I have not thought about it very hard (so I might not have considered everything)  but it seems to me that the 2 have to be in either the 1st and second or 2nd and 3rd rows.  And they cannot be seperated by an odd number of block.

So one must be in an even position and one must be in an odd position. There are 26 even positions and 26 odd positions.

So maybe

26*26*2*2 = 2704 ways

Sorry, I don't quite know what you want, but here is what I understand:

 sin(x)/sin(y)=sin(x) * csc(y)

5n+34=-2(1-7n)

n=4

3n-5=-8(6+5n)

n=-1

-3(4x+3)+4(6x+1)=43

x=4

y = 0.5x + 79

x = 2 (y-79)

You mean x^2 * x^2=x^4

LCM of 2,10, and 25

Factor all the numbers: 2 x 2 x 5 x 5 x 5, for every pair of similar numbers we take only 1 of them, so

we have: 2 x 5 x 5 =50, which is your LCM

Your answer is =54 Bye.

1*1 means in computer language 1 X 1 or 1 times 1.