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 f = V / W, Where f=frequency, V=Velocity of the wave, W=wavelength of the wave.

W=h/p, where h=Planck's Constant, p=is the momentum of the particle.

p=m x v, m=mass of the body, v=the velocity of the particle.

From these 3 formulas, you should be able to calculate the wavelength and the frequency of the electron. You can look up the Planck's Constant.

20/1 divided by 1/4 is the same as 20/1 multiplied by 4 so the answer is 80. 

Since the lightning flash & thunder are 45 =Km. away, or 45,000 meters away. But since sound travels at 333 m/s, then by the time it gets to your ear would be 45,000/333=135.14 seconds, or about 2 minutes and 15 seconds before you hear it. You will see the light flash almost instantaniously, because 45 Km from you, it will only takes it: 1/((3 x 10^8)/45000)=1/6,667 of a second to reach your eye.

Well, why don't you just mulyiply the 1st. two numbers thus: 28 X 4=112 and divide this number by 2 and it gives you=56. Was that difficult?

(w-7)(w+1) smiplify your answer,

It's a Parabola,

its extended form is:

w^2 -6w -7 and its roots are,

w=-1 and w=7

Right angle triangle oriented with the right angle in the bottom left. At the top is a 37 degree angle and the hypotenuse is 15 miles long what is the length of the bottom side?

You use the sine function, Sin(37)=Opposite side/Hypotenuse=.601815023152=Opp/15, then the Opposite side=.601815023152 x 15=9.02722534728, which is the bottom side.

0/0 =100-100/100-100= 10²-10²/10²-10²=[10+10][10-10]/10[10-10] =10+10/10=20/10=2

hence proved

x-3y=16

This has MANY solutions such as: x=1, y=-5 or x=4, y=-4, x=7, y=-3.....etc.

2x+5y=-1

This also has MANY solutions such as, x=7, y=-3 or x=2, y=-1.......etc.

The future value of an annuity due of $10,000 per year for 20 years at 5% interest is

Assuming interest ia compounded annualy and payments are made at the beginning of the year, the FV  value of the annuity =$347,192.52

ohms law is where in a math equation you get out of your house and twerk bitc h

just use the minus sign above the plus

under the 2 right of the 0

CPhill.. im really impressed!

Just started a new school and im kinda not that good when it comes to math in general. But im trying my best to learn

more.  The question you gave me just made alot of sence and i totaly understand why it's so! :D

The reason why i asked this is that we have a few exercises that we can use to get better and math is involved.

The question is basically

How much energy do you use to heat up 1,75 kg water from 6c(celcius) to 92c(celcius)

specific heat capacity for water is 4,19*10^3. So if i follow this E=c*m*delta T ( Energy = specific heat capacity for water * mass*temperature change) ?=4,19*10^3*1,75*86

The answere is: 6,3*10^2kJ

I have no idea how it became 6,3*10^2 and not 10^5 ?

4,19 * 10^3 *1,75 *86  = 630.595 x 10^3

In scientific notation this would be written as  6.30595 x 10^5

I think you may mean :  15 cm to 12 cm rate of decrease

So we have

[15 - 12 ] / 15  =   3/15 =  1/5   = .20 ......  or 20%  rate of decrease

For a rate you need two units.

like

miles/ hour

or

words/page

You only have one unit ( cm ) so you cannot turn it inato a rate.      

Using Calculus, we can show that the shortest distance occurs when :

tan (APC) = tan (BPD)

Let  PC = x   and let PD = 1200 - x

So.....tan (APC) = 600/x      and tan (BPD)  =  300/(1200 - x)

So we have :

600/x = 300 / (1200 - x)     →  2/x = 1/(1200 - x)     cross multiply

2(1200 - x)  = x

2400 - 2x  = x     add 2x to both sides

2400 = 3x      divide both sides by 3

800 = x  = PC  ......  So  he should aim for point P, 800 ft from point C

-15 + 9 -12   =

-6 -12  =

-18 ft. 

[Or, 18 ft. below sea level]

I was already lookin when Chris answered so I am going to finish my answer too :)

I am going to let the train that is travelling at x km/hour be at point 0

and I am going to let the train that is travelling at -y km/hour be at  d

AT any point T in time  the trains will be at point  xT and  d-yT

They will be at the same point when  

xT=d-yT

xT+yT=d

T(x+y)=d

T=d/(x+y)

At this point in time the trains will be at  dx / (x+y)

It is easier to work out this formula by doing it with the numbers first.    

-------

Using the fromula for you situation

x=5   y=3   and d=100

100*5 / 8

=500/8

= 62.5 km from the x start point 

Just as Chris said :))

I like the way you did that, Melody  !!!

Let the speed of one be x m/s  .......and let the other be y m/s......and let the distance between them be d

Tnen ......Rate x Time = Distance......and each of them travels the same amount of time

So.....   x * t  + y * t = d    or, solving for t, we have  t (x + y) = d  →  t = d / (x + y)

So....the distance that the train moving at x m/s  will tavel is  just x * (d / [ x + y] )

And the distance that the train moving at y m/s will travel is just y * (d / [x + y])

Let's use your example:

3*t + 5*t = 100 

t = 100/(3 + 5)  = 100/8  = 12.5 sec

So....this is how long before the trains meet

The train moving at 3m/s travels  3(12.5)  = 37.5m

And the train moving at 5m/s travels  5(12.5)  = 62.5m

So.....they meet at a point either 37.5m from where the slower train starts or at a point 62.5m from where the faster train starts, depending upon your preference.....

25 = 5^2      perhaps that is what you want :)

3/100 * 3998 =

1 - 2/7  -  3/5

That is assuming no one walks or rides a bike or .......

Not sure that my answer is correct as my states wouldn't consist of just 1s and 0s.