Car A has a head start of 10 seconds/3600 (65km/hr)
Car A position is 10/3600 (65) + 65 t
Car B position is 70 t
WHen they are equal, car B will be caught up to Car A
10/3600 (65) + 65 t = 70 t
650/3600 = 5 t
t =130/3600 of an hour or 130 seconds
Checking: Car A Position after 130 seconds (+ 10 second head start) = 140/3600 (65km/hr) = 2.527 km from 'start line'
Car B position after 130 seconds = 130/3600 (70km/hr) = 2.527 km from 'start line'
SORRY.... I had wrong speed value for car B in my original submission......!